Plane \(z = 10 \) m carries charge 48\( nC/m^2\). The electric field intensity at the origin is;O 864-n \(\mathbf{a_x}\)O 1728-t \(\mathbf{a_z}\)O -864-n \(\mathbf{a_z}\)2 - 1728 n \(\mathbf{a_y}\)

We need to find electric field for given charge density .

Answered: Plane \(z = 10 \) m carries charge 48\(…

Plane \(z = 10 \) m carries charge 48\( nC/m^2\). The electric field intensity at the origin is; 864 n \(\mathbf{a_x}\) O 1728-n \(\mathbf{a_z}\) O -864n \(\mathbf{a_z}\) 2 -1728-n \(\mathbf{a_y}\)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Plane \(z = 10 \) m carries charge 48\( nC/m^2\). The electric field intensity at the origin is;
O 864-n \(\mathbf{a_x}\)
O 1728-t \(\mathbf{a_z}\)
O -864-n \(\mathbf{a_z}\)
2 - 1728 n \(\mathbf{a_y}\)

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Plz solve within 30min I vill give definitely upvote and vill give positive feedback thank you sir