Plane-polarized light is incident on a single polarizing disk with the direction of E, parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of: (a) 2.80 (b) 4.80 (c) 11.6

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### Polarization and Light Intensity Reduction

##### Problem Statement:
Plane-polarized light is incident on a single polarizing disk with the direction of \(\vec{E}_0\) (the electric field vector) parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of:

#### Options:
(a) 2.80° 

(b) 4.80° 

(c) 11.6°

---

In this problem, we are exploring the angle through which a polarizing disk must be rotated to achieve a specific reduction in the intensity of the transmitted beam. When linearly polarized light passes through a polarizer whose axis is at an angle \( \theta \) to the polarization direction of the light, the intensity \( I \) of the transmitted light is given by Malus's Law:

\[ I = I_0 \cos^2 \theta \]

Where:
- \( I_0 \) is the initial intensity of the light.
- \( I \) is the transmitted intensity.
- \( \theta \) is the angle between the light’s initial polarization direction and the axis of the polarizer.
Transcribed Image Text:### Polarization and Light Intensity Reduction ##### Problem Statement: Plane-polarized light is incident on a single polarizing disk with the direction of \(\vec{E}_0\) (the electric field vector) parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of: #### Options: (a) 2.80° (b) 4.80° (c) 11.6° --- In this problem, we are exploring the angle through which a polarizing disk must be rotated to achieve a specific reduction in the intensity of the transmitted beam. When linearly polarized light passes through a polarizer whose axis is at an angle \( \theta \) to the polarization direction of the light, the intensity \( I \) of the transmitted light is given by Malus's Law: \[ I = I_0 \cos^2 \theta \] Where: - \( I_0 \) is the initial intensity of the light. - \( I \) is the transmitted intensity. - \( \theta \) is the angle between the light’s initial polarization direction and the axis of the polarizer.
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