plane π is said to be tangent to a spherical surface with center C and radius r if the distance from C to π is equal to r and, where P is the point of tangency, the vector CP is a vector normal to π. Check the alternative that contains the equation of the spherical surface with center C(2,4,5) and tangent to the plane π:x+2y−2z−2=0. Choose the correct alternative: a. x2−36x+y2−72y+z2−90z+72=0 b.9x2−36x+9y2−72y+9z2−90z+401=0 c.x2−36x+y2−72y+z2−90z+397=0 d.9x2−36x+9y2−72y+9z2−90z+72=0 e.9x2−36x+9y2−72y+9z2−90z

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