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plane π is said to be tangent to a spherical surface with center C and radius r if the distance from C to π is equal to r and, where P is the point of tangency, the vector CP is a vector normal to π. Check the alternative that contains the equation of the spherical surface with center C(2,4,5) and tangent to the plane π:x+2y−2z−2=0. Choose the correct alternative: a. x2−36x+y2−72y+z2−90z+72=0 b.9x2−36x+9y2−72y+9z2−90z+401=0 c.x2−36x+y2−72y+z2−90z+397=0 d.9x2−36x+9y2−72y+9z2−90z+72=0 e.9x2−36x+9y2−72y+9z2−90z

plane π is said to be tangent to a spherical surface with center C and radius r if the distance from C to π is equal to r and, where P is the point of tangency, the vector CP is a vector normal to π. Check the alternative that contains the equation of the spherical surface with center C(2,4,5) and tangent to the plane π:x+2y−2z−2=0. Choose the correct alternative: a. x2−36x+y2−72y+z2−90z+72=0 b.9x2−36x+9y2−72y+9z2−90z+401=0 c.x2−36x+y2−72y+z2−90z+397=0 d.9x2−36x+9y2−72y+9z2−90z+72=0 e.9x2−36x+9y2−72y+9z2−90z

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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A plane π is said to be tangent to a spherical surface with center C and radius r if the distance from C to π is equal to r and, where P is the point of tangency, the vector CP is a vector normal to π. Check the alternative that contains the equation of the spherical surface with center C(2,4,5) and tangent to the plane π:x+2y−2z−2=0.

Choose the correct alternative:

a. x2−36x+y2−72y+z2−90z+72=0

b.9x2−36x+9y2−72y+9z2−90z+401=0

c.x2−36x+y2−72y+z2−90z+397=0

d.9x2−36x+9y2−72y+9z2−90z+72=0

e.9x2−36x+9y2−72y+9z2−90z+397=0

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