Places) Part 5 of 8 Since x2 and x3 don't agree to eight decimal places, we must find another iteration. X36 - 48 X4 = X3 x(rounded to eight decimal places)
Places) Part 5 of 8 Since x2 and x3 don't agree to eight decimal places, we must find another iteration. X36 - 48 X4 = X3 x(rounded to eight decimal places)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Part 4 of 8**
Now we can find \( x_3 \).
\[
x_3 = 1.91666667 - \frac{1.91666667^6 - 48}{6 \left( (1.966667 \times 1.91666667) \right)^5}
\]
The calculation simplifies to:
\[
= 1.9065059257 \approx 1.90650593 \, \text{(rounded to eight decimal places)}
\]
**Part 5 of 8**
Since \( x_2 \) and \( x_3 \) don't agree to eight decimal places, we must find another iteration.
\[
x_4 = x_3 = \frac{x_3^6 - 48}{6 \times x_3^5}
\]
The calculation results in a placeholder output from which the exact value needs verification.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2092b6ff-c2fa-4fb1-b46b-a8cab8f92b86%2Fe95258e7-afb9-469e-ae94-3f72c6d72ae6%2F2gdrg86_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Part 4 of 8**
Now we can find \( x_3 \).
\[
x_3 = 1.91666667 - \frac{1.91666667^6 - 48}{6 \left( (1.966667 \times 1.91666667) \right)^5}
\]
The calculation simplifies to:
\[
= 1.9065059257 \approx 1.90650593 \, \text{(rounded to eight decimal places)}
\]
**Part 5 of 8**
Since \( x_2 \) and \( x_3 \) don't agree to eight decimal places, we must find another iteration.
\[
x_4 = x_3 = \frac{x_3^6 - 48}{6 \times x_3^5}
\]
The calculation results in a placeholder output from which the exact value needs verification.
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