пk the HOwing in termsS Of increasing bolling poOint: CH3CH2OCH2CH3 CH3CH2OCH3 CН:CH-CH2CH3 CH3CH2CH2CH2N a. CH3CH2OCH3< CH3CH2CH2CH3< CH3CH2OCH2CH3
пk the HOwing in termsS Of increasing bolling poOint: CH3CH2OCH2CH3 CH3CH2OCH3 CН:CH-CH2CH3 CH3CH2CH2CH2N a. CH3CH2OCH3< CH3CH2CH2CH3< CH3CH2OCH2CH3
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter9: Liquids, Solids, And Materials
Section: Chapter Questions
Problem 104QRT: Consider this information regarding two compounds. Thallium azide: yellow crystalline solid; melting...
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![1. Rank the following in terms of increasing boiling point:
CH3CH2OCH2CH3
CH3CH2OCH3
CH3CH2CH2CH3
CH3CH2CH2CH2NH2
a. CH3CH2OCH3< CH3CH2CH2CH3< CH3CH2OCH2CH3<CH3CH2CH2CH2NH2
b.CH3CH2CH2CH3< CH3CH2OCH3< CH;CH2OCH2CH3<CH3CH2CH2CH2NH2
c. CH3CH2CH2CH2NH2< CH3CH2OCH2CH3 < CH;CH2OCH3 < CH3CH2CH2CH3
d.CH3CH2CH2CH2NH2< CH3CH2CH2CH3< CH3CH2OCH3 < CH3CH2OCH2CH3
2. Place the following compounds in order of decreasing strength of intermolecular forces.
I. CH3CH2CH2CH2CH2CH3
П. (СН3)3ССН3
I. (СН3)3ССH2CH3
А) II > I >I
В)I > I > I
C) I > II > III
D) II > Ш >I
E) II > I > П
3. The normal boiling point for H Br is higher than the normal boiling point for H Cl. This can be
explained by
A) larger dipole-dipole forces for H Br .
B) larger dispersion forces for H Br .
C) larger hydrogen-bond forces for H Br.
D) larger dipole-dipole forces, larger dispersion forces, and larger hydrogen-bond forces for H Br .
4. Place the following substances in order of increasing boiling point.
А) Не < I2 < 02
B) I2 < 02 < He
С) 02 < I2 < Не
D) I2 < He < 02
E) He < 02 < I2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F082b1d83-0750-4b09-9a00-f69c5dcce16e%2Fd3acb393-38f8-4a48-8823-1c55802de6b9%2F7w7w42v_processed.png&w=3840&q=75)
Transcribed Image Text:1. Rank the following in terms of increasing boiling point:
CH3CH2OCH2CH3
CH3CH2OCH3
CH3CH2CH2CH3
CH3CH2CH2CH2NH2
a. CH3CH2OCH3< CH3CH2CH2CH3< CH3CH2OCH2CH3<CH3CH2CH2CH2NH2
b.CH3CH2CH2CH3< CH3CH2OCH3< CH;CH2OCH2CH3<CH3CH2CH2CH2NH2
c. CH3CH2CH2CH2NH2< CH3CH2OCH2CH3 < CH;CH2OCH3 < CH3CH2CH2CH3
d.CH3CH2CH2CH2NH2< CH3CH2CH2CH3< CH3CH2OCH3 < CH3CH2OCH2CH3
2. Place the following compounds in order of decreasing strength of intermolecular forces.
I. CH3CH2CH2CH2CH2CH3
П. (СН3)3ССН3
I. (СН3)3ССH2CH3
А) II > I >I
В)I > I > I
C) I > II > III
D) II > Ш >I
E) II > I > П
3. The normal boiling point for H Br is higher than the normal boiling point for H Cl. This can be
explained by
A) larger dipole-dipole forces for H Br .
B) larger dispersion forces for H Br .
C) larger hydrogen-bond forces for H Br.
D) larger dipole-dipole forces, larger dispersion forces, and larger hydrogen-bond forces for H Br .
4. Place the following substances in order of increasing boiling point.
А) Не < I2 < 02
B) I2 < 02 < He
С) 02 < I2 < Не
D) I2 < He < 02
E) He < 02 < I2
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