College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![Pipe ti
of 0.8m. WI
and adjacent
10. The longes
What is the lo
the pipe is (a)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fedc85e3b-dc2d-4f8b-a097-9d7c53c76aad%2F62061422-a45c-4075-a238-17f684a05a82%2Fve0qf5k_reoriented.jpeg&w=3840&q=75)
Transcribed Image Text:Pipe ti
of 0.8m. WI
and adjacent
10. The longes
What is the lo
the pipe is (a)
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given data:
The length of pipe with one end closed is: L = 0.8 m
The distance between a node and adjacent anti-node of its second harmonic is: d
(9)The air column in a closed pipe vibrates with one and a half loops (1+1/2 = 3/2) in its second harmonic. It contains two nodes and two antinodes. Hence,
The length of one and half-loop = length of pipe = L = 0.8 m. Thus,
The length of half-loop will be = L/3 = 0.8/3 = 0.267 m.
The length of the half-loop is nothing but the difference between nodes and adjacent antinodes.
Thus, the distance between a node and adjacent anti-node of its second harmonic is 0.267 m.
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