PID Example #1 OP₁ = OP + P[dE + E dT/I + D d(dPV)/dT] n-1 Note: P=2, I=10, D=1, dT=1 Time (Second) SP 0 10 1 10 2 10 PV 11 11 11 E 1 1 1 dE dPV d(dPV) OP (Init = 55) 0 0 0 55.2 0 0 0 0 0 0 55.4 55.6
PID Example #1 OP₁ = OP + P[dE + E dT/I + D d(dPV)/dT] n-1 Note: P=2, I=10, D=1, dT=1 Time (Second) SP 0 10 1 10 2 10 PV 11 11 11 E 1 1 1 dE dPV d(dPV) OP (Init = 55) 0 0 0 55.2 0 0 0 0 0 0 55.4 55.6
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![OP₁
Note: P=2, I=10, D=1, dT=1
PID Example #1
OP-1+P[dE+ EdT/I + D d(dPV)/dT]
=
0
1
2
Time (Second) SP
10
10
10
PV
11
11
11
E
1
1
1
dE dPV
0
0
0
0
0
0
d(dPV) OP (Init=55)
0
55.2
0
0
55.4
55.6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78960e1e-98e1-4b0f-bc7a-eaca82c08b7c%2F4d337c4d-5abe-4d23-b457-ba8da505f6e6%2Fhcb1kp7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:OP₁
Note: P=2, I=10, D=1, dT=1
PID Example #1
OP-1+P[dE+ EdT/I + D d(dPV)/dT]
=
0
1
2
Time (Second) SP
10
10
10
PV
11
11
11
E
1
1
1
dE dPV
0
0
0
0
0
0
d(dPV) OP (Init=55)
0
55.2
0
0
55.4
55.6
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