:Pick up the incorrect statement from the following The straight distance between end points of a suspended tape is reduced by an amount called the sag correction While measuring a distance with a tape of length 100.005 m, the distance to be increasing by 0.005 m for each tape length A 100 m tape of cross section 10 mm x 0.25 mm stretches about 10 mm under 5 kg pull An increase in temperature causes a tape to increase in length and the measured distance is too large

:Pick up the incorrect statement from the following The straight distance between end points of a suspended tape is reduced by an amount called the sag correction While measuring a distance with a tape of length 100.005 m, the distance to be increasing by 0.005 m for each tape length A 100 m tape of cross section 10 mm x 0.25 mm stretches about 10 mm under 5 kg pull An increase in temperature causes a tape to increase in length and the measured distance is too large

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A steel tape of nominal length 200 m with a plumb bob of mass 16 kg attached to it was used to measure a length down a shaft as 160.852 m. The mean temperature during the measurement was 4 C. If the tape was standardized to be 200.0014m under a tension of 115 N at 20" C temperature, determine the correct measured length. The following data may be used: Mass of tape = 0.07 kg/m Cross-sectional area of tape= 10 mm Coefficient of linear expansion a = 11x 10/°C Modulus of clasticity = 2x 10° Nmm Acceleration due to gravity 9.807 m's.
I need a handwritten solution for this, Thank you!
Solve the question below. Show your complete solution.
Answer the problem question then use 4 decimal places as final answer ( Examples of 2 decimal: 24.077 write as 24.08) Then box the final answer. Don’t forget the unit. Take note: Write it on a piece of paper, handwritten show your solution.
In the given figure below, a tube was supported at A and E with a ball and socket and a wire at D connected to F. Determine the following give that Force F is equal to 690.86 N. Note: Express your answer in terms of the units. Observe 3 decimal places. The error threshold is ± 2.50% Relative to the right answer. XB: 188.419mm Xc: 471.768mm Ya: 209.808mm Ze: 155.444 mm Zf: 471.096 mm 5.) Determine the x-component of the moment experienced by the system assuming that there is no wire support. 6.) Determine the y-component of the moment experienced by the system assuming that there is no wire support. 7.) Determine the z-component of the moment experienced by the system assuming that there is no wire support. 8.) Determine the Tension experienced by the wire DF.
A person by the name of Sutterland has developed a correlation that can be used to evaluate the viscosity of air as a function of temperature. It is given by
For this problem, I used the conjugate beam method to help solve for what’s asked. How would I calculate the deflection between A and B (red line numbered 2) and the deflection to the left of the 10 ( red line numbered 1). The beam in the picture is already in the conjugate form now. Now I just need deflections.
The force—deflection relationships for three springs are shown in the accompanying figure. What is the stiffness (spring constant) of each spring? Which one of the springs is the stiffest?
The position of a particle moving along the x-axis is given by x (t) = 5.0 - 2.0t m. (a) at what time does the particle cross the origin? (b) what is the displacement of the particle between t = 4.0 s and t = 8.0 s?
The position of a particle is given by s = 0.30t³ -0.70t² - 2.50t + 4.99, where s is in feet and the time t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 8 seconds of motion. After you have the plots, answer the questions as a check on your work. Questions: 0 1 When t = 1.8 sec, V = When t = 6.5 sec, V = ●+ 2 i i +s, ft ft/sec, ft/sec, The positive time at which the particle changes direction is i a = a = i i sec. ft/sec² ft/sec²
Calculate the value of coefficient of friction if normal force on object is 765 N and friction force on object is 334 N
What will be the value of Poisson's ratio if G/K 0.6 =