Pick any two substances with indices of refraction higher than air. Calculate the critical angle for this
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Pick any two substances with indices of refraction higher than air. Calculate the critical angle for this situation.
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- A fiber optic is made with a material that has an index of refraction of 1.83. What would the critical angle for this material be at the border between it and air?State the approximate value of the critical angle for (a) glass- air surface (b) water- air surface.Part of your refraction experiment is on performing a total internal reflection. You measure the critical angle for some oil as 40o. Therefore the refractive index of that oil should be Group of answer choices 2.02 1.56
- The index of refraction for red light in water is 1.331 and that for blue light is 1.340. If a ray of white light enters the water at an angle of incidence of 50.15°, what are the underwater angles of refraction for the blue and red components of the light? (Enter your answers to at least two decimal places.) (a) blue component (b) red componentThe index of refraction for red light in water is 1.331 and that for blue light is 1.340. If a ray of white light enters the water at an angle of incidence of 73.25°, what are the underwater angles of refraction for the blue and red components of the light? (Enter your answers to at least two decimal places.) (a) blue component °(b) red componentA 3.87 m long pole stands vertically in a lake having a depth of 2.07 m. When the Sun is 38.2o above the horizontal, determine the length of the pole's shadow on the bottom of the lake. Take the index of refraction for water to be 1.33.
- You can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction of a substance that has a critical angle of 51.0° when submerged in carbon tetrachloride, which has an index of refraction of 1.461? (b) What would the critical angle be for this substance in air?Fiber optic cables, such as those used for high-speed communication (Internet & phone services), transmit signals as light pulses through transparent cables. When viewed from one of the ends, you can see these light pulses, but when viewed from the side you can't. Using your knowledge about reflection and refraction, explain how this might work. Is there some physical limitation where this might not work?