### Question 1 The resistivity of gold is \(2.44 \times 10^{-8} \, \Omega \cdot m\) at a temperature of 20°C. A gold wire, 0.5 mm in diameter and 44 cm long, carries a current of 380 mA. The number of electrons per second passing a given cross section of the wire is closest to: - \(2.4 \times 10^{18}\) - \(2.8 \times 10^{14}\) - \(2.4 \times 10^{17}\) - \(6.3 \times 10^{15}\) - \(1.2 \times 10^{22}\) --- Below the question multiple-choice options, you will find an instructional text: #### Instructions Click **Save and Submit** to save and submit. Click **Save All Answers** to save all answers. --- There are no graphs or diagrams in the image. The content is mainly focused on the properties of a gold wire and the calculation of electrons passing through a cross section of this wire. The calculation of these values is dependent on the given resistivity, dimensions, and current of the wire.

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Chapter1: Units, Trigonometry. And Vectors
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### Question 1

The resistivity of gold is \(2.44 \times 10^{-8} \, \Omega \cdot m\) at a temperature of 20°C. A gold wire, 0.5 mm in diameter and 44 cm long, carries a current of 380 mA. The number of electrons per second passing a given cross section of the wire is closest to:

- \(2.4 \times 10^{18}\)
- \(2.8 \times 10^{14}\)
- \(2.4 \times 10^{17}\)
- \(6.3 \times 10^{15}\)
- \(1.2 \times 10^{22}\)

---

Below the question multiple-choice options, you will find an instructional text:

#### Instructions
Click **Save and Submit** to save and submit. Click **Save All Answers** to save all answers.

---

There are no graphs or diagrams in the image. The content is mainly focused on the properties of a gold wire and the calculation of electrons passing through a cross section of this wire. The calculation of these values is dependent on the given resistivity, dimensions, and current of the wire.
Transcribed Image Text:### Question 1 The resistivity of gold is \(2.44 \times 10^{-8} \, \Omega \cdot m\) at a temperature of 20°C. A gold wire, 0.5 mm in diameter and 44 cm long, carries a current of 380 mA. The number of electrons per second passing a given cross section of the wire is closest to: - \(2.4 \times 10^{18}\) - \(2.8 \times 10^{14}\) - \(2.4 \times 10^{17}\) - \(6.3 \times 10^{15}\) - \(1.2 \times 10^{22}\) --- Below the question multiple-choice options, you will find an instructional text: #### Instructions Click **Save and Submit** to save and submit. Click **Save All Answers** to save all answers. --- There are no graphs or diagrams in the image. The content is mainly focused on the properties of a gold wire and the calculation of electrons passing through a cross section of this wire. The calculation of these values is dependent on the given resistivity, dimensions, and current of the wire.
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