Problem 1: Initially, the switch in Fig 1. is in its position A and capacitors C₂ and C3 are uncharged. Then the switch is flipped to position B. Afterward, what are the charge on and the potential dif- ference across each capacitor? Partial answer: AV₁ = 55 V, AV₂ = 33.5 V. a) While the capacitor is in position A, as shown in Fig.1, com- pute the charge Q accumulated on the plates of the capacitor C₁. b) After the switch is flipped to the position B, the battery is no longer connected to the contour and the charge redistributes between the ca- pacitors as shown in Fig.2. Notice that I used the fact that the segment between the capacitors C₂ and C3 has to be neutral (therefore, they have the same charge), but the segments connecting C₁ to C₂ and C₁ to C, are not neutral. What can you say about the sum of charges Q1 and Q2? Switch + 100V A C₁ISμF _C₁₂=20μF 100V -Q₁ C₂=30μF FIG. 1: The scheme for Problem 1 Q2 Q2 +Q₂ Q2 FIG. 2: The scheme for Problem lb c) Use Kirchhoff's loop law to get another relation between charges Q₁ and Q2. Starting from point B in Fig.2, move counterclockwise along the loop and register the potential differences that you encounter when crossing the capacitors (pay attention to the signs - when you move from a positively charged to a negatively charged plate, the potential is decreasing). The sum of all potential differences has to be zero. d) You answers to parts b) and c) give you a system of two equations that you can solve to find individual values of charges Q1 and Q2. Solve it to find the values of the charges, and then compute the potential differences across each capacitor.