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### Understanding Manometers for Measuring Blood Pressure In this section, we will explore how a standard mercury manometer is used to measure a patient’s blood pressure. Manometers function by measuring the difference in height of the liquid on the "open" side and the "gauge" side. #### Diagram Explanation: The diagram above shows a U-shaped manometer, with one side open to the atmosphere and the other side connected to the gauge. The difference in height (h) of the liquid column on both sides represents the pressure difference. #### Questions and Solutions: 1. **Using a Standard Mercury Manometer** a. *If the absolute pressure on the gauge side during systolic pressure is \(1.19 \times 10^5 \, \text{Pa}\), what is the gauge pressure in Pascal and in mmHg?* To find the gauge pressure: - Absolute pressure = \(1.19 \times 10^5 \, \text{Pa}\) - Atmospheric pressure \( \approx 1.01 \times 10^5 \, \text{Pa}\) - Gauge pressure = Absolute pressure - Atmospheric pressure - Gauge pressure = \(1.19 \times 10^5 \, \text{Pa} - 1.01 \times 10^5 \, \text{Pa} = 0.18 \times 10^5 \, \text{Pa}\) Convert gauge pressure to mmHg: - \(1 \, \text{atm} = 760 \, \text{mmHg} \approx 1.01 \times 10^5 \, \text{Pa}\) - \(1 \, \text{Pa} = \frac{760}{1.01 \times 10^5} \, \text{mmHg}\) - Gauge pressure in mmHg = \(0.18 \times 10^5 \, \text{Pa} \times \frac{760 \, \text{mmHg}}{1.01 \times 10^5 \, \text{Pa}}\) - Gauge pressure in mmHg = \(135.6 \, \text{mmHg}\) b. *If you used a manometer filled with trichlorofluoromethane (CFC13), a CFC refrigerant, instead of mercury,

### Understanding Manometers for Measuring Blood Pressure In this section, we will explore how a standard mercury manometer is used to measure a patient’s blood pressure. Manometers function by measuring the difference in height of the liquid on the "open" side and the "gauge" side. #### Diagram Explanation: The diagram above shows a U-shaped manometer, with one side open to the atmosphere and the other side connected to the gauge. The difference in height (h) of the liquid column on both sides represents the pressure difference. #### Questions and Solutions: 1. **Using a Standard Mercury Manometer** a. *If the absolute pressure on the gauge side during systolic pressure is \(1.19 \times 10^5 \, \text{Pa}\), what is the gauge pressure in Pascal and in mmHg?* To find the gauge pressure: - Absolute pressure = \(1.19 \times 10^5 \, \text{Pa}\) - Atmospheric pressure \( \approx 1.01 \times 10^5 \, \text{Pa}\) - Gauge pressure = Absolute pressure - Atmospheric pressure - Gauge pressure = \(1.19 \times 10^5 \, \text{Pa} - 1.01 \times 10^5 \, \text{Pa} = 0.18 \times 10^5 \, \text{Pa}\) Convert gauge pressure to mmHg: - \(1 \, \text{atm} = 760 \, \text{mmHg} \approx 1.01 \times 10^5 \, \text{Pa}\) - \(1 \, \text{Pa} = \frac{760}{1.01 \times 10^5} \, \text{mmHg}\) - Gauge pressure in mmHg = \(0.18 \times 10^5 \, \text{Pa} \times \frac{760 \, \text{mmHg}}{1.01 \times 10^5 \, \text{Pa}}\) - Gauge pressure in mmHg = \(135.6 \, \text{mmHg}\) b. *If you used a manometer filled with trichlorofluoromethane (CFC13), a CFC refrigerant, instead of mercury,

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Understanding Manometers for Measuring Blood Pressure In this section, we will explore how a standard mercury manometer is used to measure a patient’s blood pressure. Manometers function by measuring the difference in height of the liquid on the "open" side and the "gauge" side. #### Diagram Explanation: The diagram above shows a U-shaped manometer, with one side open to the atmosphere and the other side connected to the gauge. The difference in height (h) of the liquid column on both sides represents the pressure difference. #### Questions and Solutions: 1. **Using a Standard Mercury Manometer** a. *If the absolute pressure on the gauge side during systolic pressure is \(1.19 \times 10^5 \, \text{Pa}\), what is the gauge pressure in Pascal and in mmHg?* To find the gauge pressure: - Absolute pressure = \(1.19 \times 10^5 \, \text{Pa}\) - Atmospheric pressure \( \approx 1.01 \times 10^5 \, \text{Pa}\) - Gauge pressure = Absolute pressure - Atmospheric pressure - Gauge pressure = \(1.19 \times 10^5 \, \text{Pa} - 1.01 \times 10^5 \, \text{Pa} = 0.18 \times 10^5 \, \text{Pa}\) Convert gauge pressure to mmHg: - \(1 \, \text{atm} = 760 \, \text{mmHg} \approx 1.01 \times 10^5 \, \text{Pa}\) - \(1 \, \text{Pa} = \frac{760}{1.01 \times 10^5} \, \text{mmHg}\) - Gauge pressure in mmHg = \(0.18 \times 10^5 \, \text{Pa} \times \frac{760 \, \text{mmHg}}{1.01 \times 10^5 \, \text{Pa}}\) - Gauge pressure in mmHg = \(135.6 \, \text{mmHg}\) b. *If you used a manometer filled with trichlorofluoromethane (CFC13), a CFC refrigerant, instead of mercury,
Transcribed Image Text:### Understanding Manometers for Measuring Blood Pressure In this section, we will explore how a standard mercury manometer is used to measure a patient’s blood pressure. Manometers function by measuring the difference in height of the liquid on the "open" side and the "gauge" side. #### Diagram Explanation: The diagram above shows a U-shaped manometer, with one side open to the atmosphere and the other side connected to the gauge. The difference in height (h) of the liquid column on both sides represents the pressure difference. #### Questions and Solutions: 1. **Using a Standard Mercury Manometer** a. *If the absolute pressure on the gauge side during systolic pressure is \(1.19 \times 10^5 \, \text{Pa}\), what is the gauge pressure in Pascal and in mmHg?* To find the gauge pressure: - Absolute pressure = \(1.19 \times 10^5 \, \text{Pa}\) - Atmospheric pressure \( \approx 1.01 \times 10^5 \, \text{Pa}\) - Gauge pressure = Absolute pressure - Atmospheric pressure - Gauge pressure = \(1.19 \times 10^5 \, \text{Pa} - 1.01 \times 10^5 \, \text{Pa} = 0.18 \times 10^5 \, \text{Pa}\) Convert gauge pressure to mmHg: - \(1 \, \text{atm} = 760 \, \text{mmHg} \approx 1.01 \times 10^5 \, \text{Pa}\) - \(1 \, \text{Pa} = \frac{760}{1.01 \times 10^5} \, \text{mmHg}\) - Gauge pressure in mmHg = \(0.18 \times 10^5 \, \text{Pa} \times \frac{760 \, \text{mmHg}}{1.01 \times 10^5 \, \text{Pa}}\) - Gauge pressure in mmHg = \(135.6 \, \text{mmHg}\) b. *If you used a manometer filled with trichlorofluoromethane (CFC13), a CFC refrigerant, instead of mercury,
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