Physics Question

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question (3)

Given data

The mass of the ship is m = 5.95 x 107 kg

The initial speed of the ship is u = 11 m/s

 

(A)

The expression for the ship's kinetic energy is given as:

KEi=12mu2

Substitute the value in the above equation.

KEi=12×5.95×107 kg×11 m/s2KEi=359.975×107 J

Thus, the initial kinetic energy is 359.975 J.

(B)

Given data

The final speed of the ship is v = 0

 

The expression for the work required to stop is given as:

W=KEW=KEf-KEiW=12mv2-12mu2

Substitute the value in the above equation.

W=12×5.95×107 kg×0 m/s-12×5.95×107 kg×11 m/s2W=-359.975×107 J

Thus, the work done to stop the ship is 359.975 x 107 J.

(C)

The amount of work done is always equal to the change in kinetic energy.

The mechanical energy summation of kinetic energy and potential energy. The potential energy is neglected. 

Thus, the work is equal to the mechanical energy.

(D)

Given data

The displacement of the ship is d = 2.75 km = 2750 m

 

The expression for the force required to stop the ship is given as:

W=F.dF=Wd

Substitute the value in the above equation.

F=359.975×107 J2750 mF=1309×103 N

Thus, the force required to stop the ship is 1309 x 103 N.

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