Physics In Exercises 67–70, (a) use the positionequation s = −16t2 + v0t + s0 to write a function thatrepresents the situation, (b) use a graphing utility tograph the function, (c) find the average rate of changeof the function from t1 to t2, (d) describe the slope of thesecant line through t1 and t2, (e) find the equation of thesecant line through t1 and t2, and (f ) graph the secant linein the same viewing window as your position function.67. An object is thrown upward from a height of 6 feet at avelocity of 64 feet per second.t1 = 0, t2 = 368. An object is thrown upward from a height of 6.5 feet ata velocity of 72 feet per second.t1 = 0, t2 = 469. An object is thrown upward from ground level at avelocity of 120 feet per second.t1 = 3, t2 = 570. An object is dropped from a height of 80 feet.t1 = 1, t2 = 2

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Physics In Exercises 67–70, (a) use the position
equation s = −16t2 + v0t + s0 to write a function that
represents the situation, (b) use a graphing utility to
graph the function, (c) find the average rate of change
of the function from t1 to t2, (d) describe the slope of the
secant line through t1 and t2, (e) find the equation of the
secant line through t1 and t2, and (f ) graph the secant line
in the same viewing window as your position function.
67. An object is thrown upward from a height of 6 feet at a
velocity of 64 feet per second.
t1 = 0, t2 = 3
68. An object is thrown upward from a height of 6.5 feet at
a velocity of 72 feet per second.
t1 = 0, t2 = 4
69. An object is thrown upward from ground level at a
velocity of 120 feet per second.
t1 = 3, t2 = 5
70. An object is dropped from a height of 80 feet.
t1 = 1, t2 = 2

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