physics class has 50 students. Of these, 17 students are physics majors and 18 students are female. Of the physics majors, six are female. Find the probability that a randomly selected student is female or a physics major. The probability that a randomly selected student is female or a physics major is Round to three decimal places as needed.)

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The image displays a word problem about probability related to a physics class. Here is the transcribed text formatted suitably for an educational website:

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**Probability Problem: Physics Class**

A physics class has 50 students. Of these, 17 students are physics majors and 18 students are female. Of the physics majors, six are female. Find the probability that a randomly selected student is female or a physics major.

**Question:**
The probability that a randomly selected student is female or a physics major is: \[ \_\_\_\_ \] (Round to three decimal places as needed.)

---

**Detailed Explanation:**

To find the probability that a randomly selected student is either female or a physics major, we can use the principle of Inclusion-Exclusion in probability:

\[ P(F \cup P) = P(F) + P(P) - P(F \cap P) \]

Where:
- \( P(F) \) is the probability that a student is female.
- \( P(P) \) is the probability that a student is a physics major.
- \( P(F \cap P) \) is the probability that a student is both female and a physics major.

Step-by-Step Calculation:

1. **Total Number of Students (N) = 50**

2. **Number of Female Students (F) = 18**
\[ P(F) = \frac{18}{50} = 0.36 \]

3. **Number of Physics Majors (P) = 17**
\[ P(P) = \frac{17}{50} = 0.34 \]

4. **Number of Female Physics Majors (F ∩ P) = 6**
\[ P(F \cap P) = \frac{6}{50} = 0.12 \]

5. **Applying the Inclusion-Exclusion Principle:**
\[ P(F \cup P) = 0.36 + 0.34 - 0.12 = 0.58 \]

Hence, the probability that a randomly selected student is either female or a physics major is \[ 0.58 \] (rounded to three decimal places).

---

**Note:** It is important to carefully follow each step of probability calculation correctly to arrive at the accurate result.
Transcribed Image Text:The image displays a word problem about probability related to a physics class. Here is the transcribed text formatted suitably for an educational website: --- **Probability Problem: Physics Class** A physics class has 50 students. Of these, 17 students are physics majors and 18 students are female. Of the physics majors, six are female. Find the probability that a randomly selected student is female or a physics major. **Question:** The probability that a randomly selected student is female or a physics major is: \[ \_\_\_\_ \] (Round to three decimal places as needed.) --- **Detailed Explanation:** To find the probability that a randomly selected student is either female or a physics major, we can use the principle of Inclusion-Exclusion in probability: \[ P(F \cup P) = P(F) + P(P) - P(F \cap P) \] Where: - \( P(F) \) is the probability that a student is female. - \( P(P) \) is the probability that a student is a physics major. - \( P(F \cap P) \) is the probability that a student is both female and a physics major. Step-by-Step Calculation: 1. **Total Number of Students (N) = 50** 2. **Number of Female Students (F) = 18** \[ P(F) = \frac{18}{50} = 0.36 \] 3. **Number of Physics Majors (P) = 17** \[ P(P) = \frac{17}{50} = 0.34 \] 4. **Number of Female Physics Majors (F ∩ P) = 6** \[ P(F \cap P) = \frac{6}{50} = 0.12 \] 5. **Applying the Inclusion-Exclusion Principle:** \[ P(F \cup P) = 0.36 + 0.34 - 0.12 = 0.58 \] Hence, the probability that a randomly selected student is either female or a physics major is \[ 0.58 \] (rounded to three decimal places). --- **Note:** It is important to carefully follow each step of probability calculation correctly to arrive at the accurate result.
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