Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction: C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l) How many grams of water would be produced by the complete ammoxidation of 17.8 moles of o-xylene?
Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction: C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l) How many grams of water would be produced by the complete ammoxidation of 17.8 moles of o-xylene?
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.19PAE: 4.19 How many metric tons of carbon are required to react with 7.83 metric tons of Fe2O3 according...
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Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction: C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l) How many grams of water would be produced by the complete ammoxidation of 17.8 moles of o-xylene?
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