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Photos MULTIPLE CHOICE Question 6 What is the volume of the cylinder shown below? 14 cm. 6 cm. HINT: V = Bh; B = area of base, h = height A 126π cm³ 84π cm³ 102π cm³ B C

Photos MULTIPLE CHOICE Question 6 What is the volume of the cylinder shown below? 14 cm. 6 cm. HINT: V = Bh; B = area of base, h = height A 126π cm³ 84π cm³ 102π cm³ B C

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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what is the volume of the cylinder shown below? 

 

**Multiple Choice** **Question 6** *What is the volume of the cylinder shown below?* [Diagram of a cylinder] - The cylinder has a height (h) of 14 cm. - The radius (r) of the base of the cylinder is 6 cm. **HINT:** \( V = Bh; B = \text{area of base}, h = \text{height} \) **Options:** A) \( 126\pi \text{ cm}^3 \) B) \( 84\pi \text{ cm}^3 \) C) \( 102\pi \text{ cm}^3 \) --- **Explanation:** To calculate the volume of a cylinder, we use the formula: \[ V = Bh \] Where \( B \) (the area of the base) is calculated as \( \pi r^2 \), and \( h \) is the height of the cylinder. In this case: \[ r = 6 \text{ cm} \] \[ h = 14 \text{ cm} \] So, \[ B = \pi r^2 = \pi (6 \text{ cm})^2 = 36\pi \text{ cm}^2 \] Finally, \[ V = Bh = 36\pi \text{ cm}^2 \times 14 \text{ cm} = 504\pi \text{ cm}^3 \] *Suggestion: Verify the options provided (none of the given options are correct based on the calculation)*.
Transcribed Image Text:**Multiple Choice** **Question 6** *What is the volume of the cylinder shown below?* [Diagram of a cylinder] - The cylinder has a height (h) of 14 cm. - The radius (r) of the base of the cylinder is 6 cm. **HINT:** \( V = Bh; B = \text{area of base}, h = \text{height} \) **Options:** A) \( 126\pi \text{ cm}^3 \) B) \( 84\pi \text{ cm}^3 \) C) \( 102\pi \text{ cm}^3 \) --- **Explanation:** To calculate the volume of a cylinder, we use the formula: \[ V = Bh \] Where \( B \) (the area of the base) is calculated as \( \pi r^2 \), and \( h \) is the height of the cylinder. In this case: \[ r = 6 \text{ cm} \] \[ h = 14 \text{ cm} \] So, \[ B = \pi r^2 = \pi (6 \text{ cm})^2 = 36\pi \text{ cm}^2 \] Finally, \[ V = Bh = 36\pi \text{ cm}^2 \times 14 \text{ cm} = 504\pi \text{ cm}^3 \] *Suggestion: Verify the options provided (none of the given options are correct based on the calculation)*.
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