Photos MULTIPLE CHOICE Question 6 What is the volume of the cylinder shown below? 14 cm. 6 cm. HINT: V = Bh; B = area of base, h = height A 126π cm³ 84π cm³ 102π cm³ B C

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter63: Volumes Of Pyramids And Cones
Section: Chapter Questions
Problem 25A
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what is the volume of the cylinder shown below? 

 

**Multiple Choice**

**Question 6**

*What is the volume of the cylinder shown below?*

[Diagram of a cylinder]

- The cylinder has a height (h) of 14 cm.
- The radius (r) of the base of the cylinder is 6 cm.

**HINT:** \( V = Bh; B = \text{area of base}, h = \text{height} \)

**Options:**

A) \( 126\pi \text{ cm}^3 \)

B) \( 84\pi \text{ cm}^3 \)

C) \( 102\pi \text{ cm}^3 \)

---

**Explanation:**

To calculate the volume of a cylinder, we use the formula:

\[ V = Bh \]

Where \( B \) (the area of the base) is calculated as \( \pi r^2 \), and \( h \) is the height of the cylinder.

In this case:
\[ r = 6 \text{ cm} \]
\[ h = 14 \text{ cm} \]

So,
\[ B = \pi r^2 = \pi (6 \text{ cm})^2 = 36\pi \text{ cm}^2 \]

Finally,
\[ V = Bh = 36\pi \text{ cm}^2 \times 14 \text{ cm} = 504\pi \text{ cm}^3 \]

*Suggestion: Verify the options provided (none of the given options are correct based on the calculation)*.
Transcribed Image Text:**Multiple Choice** **Question 6** *What is the volume of the cylinder shown below?* [Diagram of a cylinder] - The cylinder has a height (h) of 14 cm. - The radius (r) of the base of the cylinder is 6 cm. **HINT:** \( V = Bh; B = \text{area of base}, h = \text{height} \) **Options:** A) \( 126\pi \text{ cm}^3 \) B) \( 84\pi \text{ cm}^3 \) C) \( 102\pi \text{ cm}^3 \) --- **Explanation:** To calculate the volume of a cylinder, we use the formula: \[ V = Bh \] Where \( B \) (the area of the base) is calculated as \( \pi r^2 \), and \( h \) is the height of the cylinder. In this case: \[ r = 6 \text{ cm} \] \[ h = 14 \text{ cm} \] So, \[ B = \pi r^2 = \pi (6 \text{ cm})^2 = 36\pi \text{ cm}^2 \] Finally, \[ V = Bh = 36\pi \text{ cm}^2 \times 14 \text{ cm} = 504\pi \text{ cm}^3 \] *Suggestion: Verify the options provided (none of the given options are correct based on the calculation)*.
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