Phosphoric acid (H3PO4) is a triprotic acid with pKa values of 2.12, 7.21, and 12.32. It is a useful buffer solution for pH values near the pKa values. You have a 0.100 M solution of phosphate buffer with a pH of 2.50. How many mL of 0.500 M NaOH solution must be added to 1.00 L of this buffer solution to convert it to a buffer at pH 7.70? Answer in mL
Phosphoric acid (H3PO4) is a triprotic acid with pKa values of 2.12, 7.21, and 12.32. It is a useful buffer solution for pH values near the pKa values. You have a 0.100 M solution of phosphate buffer with a pH of 2.50. How many mL of 0.500 M NaOH solution must be added to 1.00 L of this buffer solution to convert it to a buffer at pH 7.70? Answer in mL
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 49P
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![Phosphoric acid (H3PO4) is a triprotic
acid with pKa values of 2.12, 7.21, and
12.32. It is a useful buffer solution for
pH values near the pKa values. You
have a 0.100 M solution of phosphate
buffer with a pH of 2.50. How many
mL of 0.500 M NaOH solution must be
added to 1.00 L of this buffer solution
to convert it to a buffer at pH 7.70?
Answer in mL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c85d146-9f2e-4f18-b716-ebf731efd2c6%2F363f0a6a-6d65-4ce1-9bf9-08b56c087238%2Ffugrdw3_processed.png&w=3840&q=75)
Transcribed Image Text:Phosphoric acid (H3PO4) is a triprotic
acid with pKa values of 2.12, 7.21, and
12.32. It is a useful buffer solution for
pH values near the pKa values. You
have a 0.100 M solution of phosphate
buffer with a pH of 2.50. How many
mL of 0.500 M NaOH solution must be
added to 1.00 L of this buffer solution
to convert it to a buffer at pH 7.70?
Answer in mL
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Step 1: Concept of Molarity
VIEWStep 2: Dissociation reaction of phosphoric acid
VIEWStep 3: Calculation of initial composition of buffer solution
VIEWStep 4: Second dissociation reaction
VIEWStep 5: Calculation of final concentrations
VIEWStep 6: Calculating the moles of hydroxide ions
VIEWStep 7: Calculation of volume of NaOH required
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