**Phosgene, COCl₂, is the chemical warfare gas commonly called mustard gas. It decomposes as written below. At 900°C, the Kc = 0.83. Assume 0.400 mol of COCl₂ are admitted into a 2.00 L container at 900°C. What will be the equilibrium concentrations of CO, Cl₂, and COCl₂? USE THE QUADRATIC for this one. You will NOT need to use quadratic on a test but for take home problems it is OK.**\[ \text{COCl}_2 \rightleftharpoons \text{CO} + \text{Cl}_2 \]\[ \text{[CO]}_{eq} = \underline{\hspace{2cm}} \]\[ \text{[Cl}_2]_{eq} = \underline{\hspace{2cm}} \]\[ \text{[COCl}_2]_{eq} = \underline{\hspace{2cm}} \]

The equilibrium concentration is the ratio of equilibrium concentration of products to the equilibrium concentration of the reactant. For a reaction the equilibrium constant will be a unique value. The given reaction is as follows. COCl2⇔CO+Cl2 The equilibrium constant for this reaction at 900 0C is 0.83.The initial concentration of COCl2 can be calculated as follows. concentration=molesvolumeL=0.4 mol2 L=0.2 mol/L=0.2 M Now we can construct ICE table. COCl2 ⇔ CO+Cl2Initial conc. 0.2 M 0 0change in conc. -x + x +xEquilibrium conc. 0.2-x x x Equilibrium concentration of this reaction can be expressed as follows. Kc=COCl2COCl2 Based on the ICE table we can find the equilibrium molarities of the given species. 0.83=x.x0.2-x0.830.2-x= x20.166-0.83x= x2x2+0.83x-0.166= 0 Now solve this quadratic equation. x=-b±b2-4ac2a=-0.83±-0.832-4×1×-0.1662×1=-0.83±0.6889+0.6642=-0.83±1.1632=-0.83+1.1632 or -0.83-1.1632=0.1665 or -0.9965 Negative value is not acceptable here. So the value of x is 0.1665.Now we can calculate the equilibrium concentration of COCl2, CO and Cl2. Equilibrium concentration of COCl2=0.2-x=0.2-0.1665=0.0335Equilibrium concentration of CO =x=0.1665Equilibrium concentration of Cl2 =x=0.1665 Hence COeq=0.1665 M, Cl2eq=0.1665 M and COCl2eq=0.0335 M

Science

Chemistry

Phosgene, COC12, is the chemical warfare gas commonly called mustard gas. It decomposes as 3) written below. At 900 C, the Kç = 0.83. Assume 0.400 mol of COCl2 are admitted into a 2.00 L container at 900C. What will be the equilibrium concentrations of CO, Cl2 and COCI2? USE THE QUADRATIC for this one. You will NOT need to use quadratic on a test but for take home problems it is OK. COC2 <=-=> CÓ + Ch [CO]eq = (Clh]eq * [COCL]eq =.

Phosgene, COC12, is the chemical warfare gas commonly called mustard gas. It decomposes as 3) written below. At 900 C, the Kç = 0.83. Assume 0.400 mol of COCl2 are admitted into a 2.00 L container at 900C. What will be the equilibrium concentrations of CO, Cl2 and COCI2? USE THE QUADRATIC for this one. You will NOT need to use quadratic on a test but for take home problems it is OK. COC2 <=-=> CÓ + Ch [CO]eq = (Clh]eq * [COCL]eq =.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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