Pharmac is a pharmaceutical company that manufactures various antacids used for symptomatic relief of heartburn. Yesterday, a batch of 250 mg calcium carbonate tablets (Brand Name: Calcarb) has been manufactured and is now up for quality control testing. Samples were transmitted to your laboratory for testing. As a laboratory analyst, you are tasked to perform the Acid Neutralizing Capacity Test. This test simulates the action of the antacid in the stomach and determines the number of milliequivalents of HCl that the antacid can neutralize. For Calcarb to pass the test, it must be able to neutralize NLT 5 mEq of HCl. Answer all subsequent questions. 1. In this test, the procedure requires that a 1 Normal Hydrochloric acid (HCl) be used. To perform the test, you need to prepare 500 mL of this acid. The available stock of HCl in the lab is concentrated HCl with a percentage concentration of 37.0% w/w. Calculate how many mL of this stock HCl must be used to prepare 500 mL of 1N HCI. The density of the stock solution is 1.2g/mL. The molar weight of HCl is 36.46 g/mol. A. 41.06 mL B. 82.12 mL C. 30.38 mL D. 164.23 mL 2. You are now about to start the test. 30 tablets will be pulverized. From the whole pulverized powders, only 2,700 mg of the powders will be subjected to the test. If one tablet corresponds to 1.35 g of powders and that each tablet has a theoretical content of 250 mg calcium carbonate, calculate how many moles of calcium carbonate is being tested. MW of calcium carbonate is 100.09 g/mol. A. 2.50 x 10^-3 moles B. 5.00 x 10^-3 moles C. 1.00 x 10^-2 moles D. 1.50 x 10^-2 moles 3. Next, the calcium carbonate powders will be mixed for a period of 15 minutes with 30 mL of the IN HCI. They are expected to react in the following way: CACO3 + 2HCI → CaCl2 + H20 + CO2 Given the number of moles of calcium carbonate that you calculated from number 2 and the reaction above, how many moles of HCl will be fully consumed if the reaction will proceed to 100% completion. A. 2.50 x 10^-3 moles B. 5.00 x 10^-3 moles C. 1.00 x 10^-2 moles D. 1.50 x 10^-2 moles 4. Given this number of moles of HCl (from the previous number), calculate how many mL of the IN HCl will be fully consumed in the test. A. 5 mL B. 10 mL C. 15 mL D. 20 mL 5. You performed the test and recorded that however, only 7 mL of IN HCl was neutralized by the antacid Calcarb. From this result, how many moles of HCl were only neutralized? A. 3.5 x 10^-3 moles B. 7x 10^-3 moles C. 1.4 x 10^-2 moles D. 2.8 x 10^-2 moles 6. Convert this calculated moles of HCl to mEq of HCl. The molar weight of HCl is 36.46 g/mol. Use a factor of 1 for HCl. A. 4 mEq of HCI B. 5 mEq of HC C. 6 mEq of HCl D. 7 mEq of HCI 7. Did calcarb pass this ANC test for this trial? A. Yes B. No

Pharmac is a pharmaceutical company that manufactures various antacids used for symptomatic relief of heartburn. Yesterday, a batch of 250 mg calcium carbonate tablets (Brand Name: Calcarb) has been manufactured and is now up for quality control testing. Samples were transmitted to your laboratory for testing. As a laboratory analyst, you are tasked to perform the Acid Neutralizing Capacity Test. This test simulates the action of the antacid in the stomach and determines the number of milliequivalents of HCl that the antacid can neutralize. For Calcarb to pass the test, it must be able to neutralize NLT 5 mEq of HCl. Answer all subsequent questions. 1. In this test, the procedure requires that a 1 Normal Hydrochloric acid (HCl) be used. To perform the test, you need to prepare 500 mL of this acid. The available stock of HCl in the lab is concentrated HCl with a percentage concentration of 37.0% w/w. Calculate how many mL of this stock HCl must be used to prepare 500 mL of 1N HCI. The density of the stock solution is 1.2g/mL. The molar weight of HCl is 36.46 g/mol. A. 41.06 mL B. 82.12 mL C. 30.38 mL D. 164.23 mL 2. You are now about to start the test. 30 tablets will be pulverized. From the whole pulverized powders, only 2,700 mg of the powders will be subjected to the test. If one tablet corresponds to 1.35 g of powders and that each tablet has a theoretical content of 250 mg calcium carbonate, calculate how many moles of calcium carbonate is being tested. MW of calcium carbonate is 100.09 g/mol. A. 2.50 x 10^-3 moles B. 5.00 x 10^-3 moles C. 1.00 x 10^-2 moles D. 1.50 x 10^-2 moles 3. Next, the calcium carbonate powders will be mixed for a period of 15 minutes with 30 mL of the IN HCI. They are expected to react in the following way: CACO3 + 2HCI → CaCl2 + H20 + CO2 Given the number of moles of calcium carbonate that you calculated from number 2 and the reaction above, how many moles of HCl will be fully consumed if the reaction will proceed to 100% completion. A. 2.50 x 10^-3 moles B. 5.00 x 10^-3 moles C. 1.00 x 10^-2 moles D. 1.50 x 10^-2 moles 4. Given this number of moles of HCl (from the previous number), calculate how many mL of the IN HCl will be fully consumed in the test. A. 5 mL B. 10 mL C. 15 mL D. 20 mL 5. You performed the test and recorded that however, only 7 mL of IN HCl was neutralized by the antacid Calcarb. From this result, how many moles of HCl were only neutralized? A. 3.5 x 10^-3 moles B. 7x 10^-3 moles C. 1.4 x 10^-2 moles D. 2.8 x 10^-2 moles 6. Convert this calculated moles of HCl to mEq of HCl. The molar weight of HCl is 36.46 g/mol. Use a factor of 1 for HCl. A. 4 mEq of HCI B. 5 mEq of HC C. 6 mEq of HCl D. 7 mEq of HCI 7. Did calcarb pass this ANC test for this trial? A. Yes B. No

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Transcribed Image Text:Pharmac is a pharmaceutical company that manufactures various antacids used for symptomatic relief of heartburn. Yesterday, a batch of 250 mg calcium carbonate tablets (Brand Name: Calcarb) has been manufactured and is now up for quality control testing. Samples were transmitted to your laboratory for testing. As a laboratory analyst, you are tasked to perform the Acid Neutralizing Capacity Test. This test simulates the action of the antacid in the stomach and determines the number of milliequivalents of HCl that the antacid can neutralize. For Calcarb to pass the test, it must be able to neutralize NLT 5 mEq of HCl. Answer all subsequent questions. 1. In this test, the procedure requires that a 1 Normal Hydrochloric acid (HCl) be used. To perform the test, you need to prepare 500 mL of this acid. The available stock of HCl in the lab is concentrated HCl with a percentage concentration of 37.0% w/w. Calculate how many mL of this stock HCl must be used to prepare 500 mL of IN HCl. The density of the stock solution is 1.2g/mL. The molar weight of HCl is 36.46 g/mol. А. 41.06 mL B. 82.12 mL C. 30.38 mL D. 164.23 mL 2. You are now about to start the test. 30 tablets will be pulverized. From the whole pulverized powders, only 2,700 mg of the powders will be subjected to the test. If one tablet corresponds to 1.35 g of powders and that each tablet has a theoretical content of 250 mg calcium carbonate, calculate how many moles of calcium carbonate is being tested. MW of calcium carbonate is 100.09 g/mol. А. 2.50 x 10^-3 moles B. 5.00 x 10^-3 moles C. 1.00 x 10^-2 moles D. 1.50 x 10^-2 moles 3. Next, the calcium carbonate powders will be mixed for a period of 15 minutes with 30 mL of the 1N HCI. They are expected to react in the following way: CACO3 + 2HCI → CaCl2 + H2O + CO2 Given the number of moles of calcium carbonate that you calculated from number 2 and the reaction above, how many moles of HCl will be fully consumed if the reaction will proceed to 100% completion. A. 2.50 x 10^-3 moles B. 5.00 x 10^-3 moles C. 1.00 x 10^-2 moles D. 1.50 x 10^-2 moles 4. Given this number of moles of HCl (from the previous number), calculate how many mL of the IN HCl will be fully consumed in the test. A. 5 mL B. 10 mL C. 15 mL D. 20 mL 5. You performed the test and recorded that however, only 7 mL of IN HCl was neutralized by the antacid Calcarb. From this result, how many moles of HCl were only neutralized? А. 3.5 x 10^-3 moles B. 7 x 10^-3 moles C. 1.4 x 10^-2 moles D. 2.8 x 10^-2 moles 6. Convert this calculated moles of HCl to mEq of HCl. The molar weight of HCl is 36.46 g/mol. Use a factor of 1 for HCI. A. 4 mEq of HCl B. 5 mEq of HC C. 6 mEq of HCi D. 7 mEq of HCI 7. Did calcarb pass this ANC test for this trial? A. Yes B. No

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