PH=3.15 c. What is the % dissociation of the formic acid? COOH DOLLS 25 = 1.77x10 3.25M (ac HCO + + OH(aq) 025- (aq) ▸ -X100

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How would you solve c?

3
3. Formic acid, HCOOH (K₂ = 1.77 x 104) is naturally found in the venom of bee stings, and is used
synthetically as a preservative in livestock feed.
a. Write the K, expression for formic acid.
Kax K₁=1.0 x· 10-14
077x10-4 x K₁=1.0×10-14 [CO] [OH-]
Kb = 5.6×10-11
ко
[HCOOHIL
[0.00660][0.00665]
[0.243] 1.82x10²4
-1.78×10-4
1682x10-4-97.25
100-9720-2.75%
"X100 -
(0) HC (69)
b. Calculate the pH of a 0.25 M solution of formic acid.
1.77x10-4 = (0,25M) [H
[H+]=7.08×10-4
PH=-10g (7.08x10-41) |
PH=3.15
c. What is the % dissociation of the formic acid?
HCOOH
0.25M
-X
0.25-x
HCO + + OH
XX
ka=
ta
z
DOLLS
.25
0
(aq) 0.25
025-1-77x10-4
x²=4.425x10-5
x=0.00665 [H-0005
X [HCCOHT=0.243 LHCO1=0.00665
px x
X₁²
Transcribed Image Text:3 3. Formic acid, HCOOH (K₂ = 1.77 x 104) is naturally found in the venom of bee stings, and is used synthetically as a preservative in livestock feed. a. Write the K, expression for formic acid. Kax K₁=1.0 x· 10-14 077x10-4 x K₁=1.0×10-14 [CO] [OH-] Kb = 5.6×10-11 ко [HCOOHIL [0.00660][0.00665] [0.243] 1.82x10²4 -1.78×10-4 1682x10-4-97.25 100-9720-2.75% "X100 - (0) HC (69) b. Calculate the pH of a 0.25 M solution of formic acid. 1.77x10-4 = (0,25M) [H [H+]=7.08×10-4 PH=-10g (7.08x10-41) | PH=3.15 c. What is the % dissociation of the formic acid? HCOOH 0.25M -X 0.25-x HCO + + OH XX ka= ta z DOLLS .25 0 (aq) 0.25 025-1-77x10-4 x²=4.425x10-5 x=0.00665 [H-0005 X [HCCOHT=0.243 LHCO1=0.00665 px x X₁²
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