Ph H H3C H Ph Br (i-Pr)₂NH

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Predict the product of the following reaction:

The image depicts a chemical reaction. The starting material is a compound featuring a central carbon atom bonded to four groups:

- A phenyl group (Ph) on a wedge, indicating it is coming out of the plane towards the observer.
- A methyl group (CH₃) on a dashed line, indicating it is going into the plane away from the observer.
- A bromine atom (Br) on a solid line, lying on the plane.
- Another phenyl group (Ph) on a dashed line, along with a hydrogen atom, indicating stereochemistry.

The reaction involves the treatment of this compound with diisopropylamine, denoted as (i-Pr)₂NH. This suggests a possible substitution or elimination reaction might occur, given the presence of bromine, a good leaving group. The mechanism and product will depend on reaction conditions such as temperature and solvent.
Transcribed Image Text:The image depicts a chemical reaction. The starting material is a compound featuring a central carbon atom bonded to four groups: - A phenyl group (Ph) on a wedge, indicating it is coming out of the plane towards the observer. - A methyl group (CH₃) on a dashed line, indicating it is going into the plane away from the observer. - A bromine atom (Br) on a solid line, lying on the plane. - Another phenyl group (Ph) on a dashed line, along with a hydrogen atom, indicating stereochemistry. The reaction involves the treatment of this compound with diisopropylamine, denoted as (i-Pr)₂NH. This suggests a possible substitution or elimination reaction might occur, given the presence of bromine, a good leaving group. The mechanism and product will depend on reaction conditions such as temperature and solvent.
Expert Solution
Step 1: Interpretation of the question

The steric halide is reacted with a strong bulk base diisopropylamine.

The alkyl halide reacts with a bulk strong base to produce an alkene.


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