Pg.5 [7] A projectile was launched vertically upward with an initial speed of 29.2 m/s from the ground. a) Find the time it takes to get to the maximum height. T-V4-29.2/9.8 V/g T= 2.97m b) Find the maximum height of the projectile., Vņ- 2gh h Valloo h= 29.2*2, h=43.5M .1 %3D c) Find its position 2 seconds later. (3pts). ut - h=29.2x2-o5x9.8x22 h=38-8m 0:5 atx2 d) When is the speed of the projectile V=-30m/s

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Chapter1: Units, Trigonometry. And Vectors
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Pg.5
[7] A projectile was launched vertically upward with an initial speed of 29.2 m/s from
the ground.
a) Find the time it takes to get to the maximum height.
T-V4-29.2/9.8
V/g
T= 2.97m
b) Find the maximum height of the projectile.,
Vņ- 2gh
h Valloo
h= 29.2*2,
h=43.5M
.1
%3D
c) Find its position 2 seconds later. (3pts).
ut -
h=29.2x2-o5x9.8x22
h=38-8m
0:5 atx2
d) When is the speed of the projectile V=-30m/s
Transcribed Image Text:Pg.5 [7] A projectile was launched vertically upward with an initial speed of 29.2 m/s from the ground. a) Find the time it takes to get to the maximum height. T-V4-29.2/9.8 V/g T= 2.97m b) Find the maximum height of the projectile., Vņ- 2gh h Valloo h= 29.2*2, h=43.5M .1 %3D c) Find its position 2 seconds later. (3pts). ut - h=29.2x2-o5x9.8x22 h=38-8m 0:5 atx2 d) When is the speed of the projectile V=-30m/s
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