Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. What is the distribution of Peter's waiting time called? (In other words, we are interested in the (random) time Peter will wait for the beginning of his service.) Point out all parameters. O Gamma distribution with parameters v= 2, a = // Exponential distribution with rate >= O Gamma-distribution with parameters = 5, a = /. O Exponential distribution with parameter a = 1/1/
Peter called to a an insurance company and was told that there was one customer ahead of him waiting for starting to be served. Suppose that at each moment, the time remaining for the next service does not depend on when the last service has begun, and the mean service time is 5 minutes. Answer Question 14-15 below. What is the distribution of Peter's waiting time called? (In other words, we are interested in the (random) time Peter will wait for the beginning of his service.) Point out all parameters. O Gamma distribution with parameters v= 2, a = // Exponential distribution with rate >= O Gamma-distribution with parameters = 5, a = /. O Exponential distribution with parameter a = 1/1/
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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