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Petangre has an area of 6O00 cm?. equation to represent length, e,as a functicn of the width, W, ter this recfanghe, 6) Write an equeation torepresant the chanme in lenan Os a function of mdth, W whan the wid this increesed by c w, of the recbeunpre a) Write an I cm. ) Determine the wicth, if the chavge in length is lo cm

Petangre has an area of 6O00 cm?. equation to represent length, e,as a functicn of the width, W, ter this recfanghe, 6) Write an equeation torepresant the chanme in lenan Os a function of mdth, W whan the wid this increesed by c w, of the recbeunpre a) Write an I cm. ) Determine the wicth, if the chavge in length is lo cm

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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reCtangre has an area of GoOo cm?. a) White an equation to represent length, e, as a fuanction of the width, W for 6) Write on equatian torepregant the charge in lendn Os a functicn of niath, W, whan thewid this ncreesed by I cm c) Deterumine the width, w, of Hhe recaungle if the chavge in lergthn fhis rectangde. s lo cm
Transcribed Image Text:reCtangre has an area of GoOo cm?. a) White an equation to represent length, e, as a fuanction of the width, W for 6) Write on equatian torepregant the charge in lendn Os a functicn of niath, W, whan thewid this ncreesed by I cm c) Deterumine the width, w, of Hhe recaungle if the chavge in lergthn fhis rectangde. s lo cm
Expert Solution
Step 1

(a)

Consider the area of a rectangle as A=6000 cm2.

Let the length and width of the rectangle be denotes as l and w.

Note that, the area of a rectangle of length l and width w is given by A=wl.

Now equate the area to 6000 and write the length l as function of w as follows:

wl=6000l=6000w

(b)

Consider the length of rectangle obtained in part (a) as l=6000w.

Differentiate the above function with respect to w as follows:

dldw=ddw6000w       =-6000w2dl=-6000w2dwdl=-6000w2    dw=1

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