Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a 70-hour review course average a score of 754. Find a linear function S(t), which fits this data, and which expresses score as a function of time. O A. S(t)=D3.35t + 519.5 O B. S(t)= 3.015t - 523.5 OC. S(t) = 3.015t + 523.5 OD. S(t)= -3.35t + 519.5

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a 70-hour review course average a score of 754. Find a linear function S(t), which fits this data, and which expresses score as a function of time. O A. S(t)=D3.35t + 519.5 O B. S(t)= 3.015t - 523.5 OC. S(t) = 3.015t + 523.5 OD. S(t)= -3.35t + 519.5

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Concept explainers

Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differential equations.

Question

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons
taking a 70-hour review course average a score of 754. Find a linear function S(t), which fits this data, and which
expresses score as a function of time.
O A. S(t)= 3.35t + 519.5
O B. S(t)= 3.015t - 523.5
OC. S(t)= 3.015t + 523.5
O D. S(t) = - 3.35t + 519.5

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