personnel director in a particular state claims that the mean annual income is greater in one of the state's counties (county A) than it is in another county (county B). In
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Q: arry your intermediate computations to three or more decimal places. (If necessary, consult a list…
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A: Given, -x1 = 893, n1 = 67, s1 = 282 -x2 = 1180, n2 = 49, s2 = 371 α = Level of significance = 0.05
Q: Students at a major university are complaining of a serious housing crunch. They complain that many…
A: Given information: Mean=μ=18Standard deviation=σ=3.9 Chebyshev's theorem: At least 75% of the…
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A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: Students at a major university are complaining of a serious housing crunch. They complain that many…
A: From the provided information, Mean (µ) = 17.4 Standard deviation (σ) = 3.5 X~N(17.4, 3.5)
Q: Students at a major university are complaining of a serious housing crunch. They complain that many…
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Q: A personnel director in a particular state claims that the mean annual income is greater in one of…
A: Solution: The claim is to test if the mean annual income is greater in country A than it is in…
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A: GivenMean(x)=722standard deviation(s)=17sample size(n)=18significance level(α)=0.10
Q: On their website, a property management company states that the mean monthly rent for apartments on…
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A: given n1=12, μ1=$827, s1=$22.8n2=8, μ1=$836, s2=$34.4
Q: A local church parish wants to raise money to add to their campus. In a sample from a previous fund…
A: Given, Sample from a previous fund raising campaign has n1=134X1=67x1=$893s1=$282 Sample proportion…
Q: A personnel director in a particular state claims that the mean annual income is greater in one of…
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A: Given: Population meanμ=675Sample size(n)=20Sample standard deviation(s)=21
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Q: local church parish wants to raise money to add to their campus. In a sample from a previous fund…
A: Formula : Test statistic
Q: A local church parish wants to raise money to add to their campus. In a sample from a previous fund…
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Q: A personnel director in a particular state claims that the mean annual income is greater in one of…
A: Given Information: County A: Sample size (n1) = 12 Sample mean (x¯1) = $40,800 Standard deviation…
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A personnel director in a particular state claims that the
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- A cell phone company offers contract phones and non-contract phones. In a sample of 40 contract subscribers, the mean yearly income was found to be $57,000 with a standard deviation of $9,200. In a sample of 30 non-contract phones, the mean yearly income was found to be $53,000 with a standard deviation of $7,100. At the 1% significance level, is there evidence that the mean annual income level between the two groups is the same? Include a p-value with your test.A regional airline serving Las Vegas has a base airfare rate of $99. In addition, various fees are charged: for checked baggage, refreshments/drinks in-flight, and for making a reservation on its website. These additional charges average $70 per passenger. Suppose a random sample of 59 passengers is taken to determine the total cost of their flight. The population standard deviation of total flight cost is known to be $40. (a) What is the population mean cost per flight in dollars? $ (b) What is the probability the sample mean will be within $10 of the population mean cost per flight? (Round your answer to four decimal places.) (c) What is the probability the sample mean will be within $5 of the population mean cost per flight? (Round your answer to four decimal places.)A random sample of 89 tourists in British Columbia showed that they spent an average of $2860 (in a week) with an assumed population standard deviation of $126; and a sample of 64 tourists in Alberta showed that they spent an average of $2935 (in a week) with an assumed population standard deviation of $138. We are interested in determining if there is any significant difference between the average expenditures of all the tourists who visited the two provinces.a. At a significance level of 0.05, are the two average expenditures significantly different? b. Calculate the 99% confidence interval and interpret your results?
- The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. Although it requires a successful completion of three levels of grueling exams, it also entails promising careers with lucrative salaries. A student of finance is curious about the average salary of a CFA charterholder. He takes a random sample of 36 recent charterholders and computes a mean salary of $129,000 with a standard deviation of $22,000. Use this sample information to determine the 99% confidence interval for the average salary of a CFA charterholder. (You may find it useful to reference the t table. Round final answers to the nearest whole number.) Confidence intervalA study was being conducted to see if people who have no college degree have a lower mean salary than those who do have a college degree. A random sample of 70 people with no college degree was taken and their mean salary was $36,950 with a standard deviation of $4,375. A random sample of 75 people with a college degree was taken and their mean salary was $41,520 with a standard deviation of $3,415. Determine the appropriate formula and calculator function that would be used to test the claim that people with no college degree have a lower mean salary at the α = 0.05 level of significance. d T-Test sa/√n Fo Zo to = 2- SampFTest P1-P₂ 1 1 √p(1-6), + n₁ n₂ (₁-x₂)-(H₁-H₂) 51 $2 + n₁ n₂ 2-PropZTest 2-SampTTestA local church parish wants to raise money to add to their campus. In a sample from a previous fund raising campaign, the parish found that of the 131 people in the sample they contacted, that 69 actually contributed money. Of those that contributed money, the average contribution was $857 with a standard deviation of $265. In the recent fundraising campaign, a sample of 95 people revealed that 48 have contributed money with an average contribution of $1109 and a standard deviation of $339. When testing (at the 5% level of significance) whether the average amount contributed has increased in the current campaign compared to the previous campaign, what is the test statistic? (please round your answer to 2 decimal places)
- Suppose the mean net worth of the resi- dents of Sun City, a retirement community, is $611,000 (Source: The Island Packet). If their net worth is nor- mally distributed with a standard deviation of $96,000,what percent of the residents have net worths between $700,000 and $800,000?A personnel director in a particular state claims that the mean annual income is greater in one of the state's counties (county A) than it is in another county (county B). In County A, a random sample of 17 residents has a mean annual income of $41,200 and a standard deviation of $8600. In County B, a random sample of 8 residents has a mean annual income of $38,600 and a standard deviation of $5200. At a=0.05, answer parts (a) through (e). Assume the population variances are not equal. If convenient, use technology to solve the problem. (a) Identify the claim and state Ho and Ha- Which is the correct claim below? A. The mean annual incomes in counties A and B are not equal." B. "The mean annual income in county A is greater than in county B." OC. "The mean annual income in county A is less than in county B." OD. "The mean annual incomes in counties A and B are equal." What are Ho and H₂? The null hypothesis, Ho, is The alternative hypothesis, H., is H1 H2 H₁ H₂ H₁ H₂On their website, a property management company states that the mean monthly rent for apartments on the east side of town is $675. A researcher for a consumer advocacy group believes that, due to the construction of newer apartment complexes in neighboring towns, the mean monthly rent on the east side, μ, is now lower. A random sample of 13 monthly rents for apartments on the east side has a mean of $673, with a standard deviation of $24. Assume that current monthly rents for apartments on the east side are approximately normally distributed. Based on the sample, is there enough evidence to conclude, at the 0.05 level of significance, that the population mean monthly rent is now less than what is stated on the website? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H. and the alternative hypothesis H₁. H₁ :0 (b) Determine the type of…
- A food distribution company claims that a restaurant chain receives, on average, 26 pounds of fresh vegetables on a daily basis. The standard deviation of these shipments is known to be 4.4 pounds. The district manager of the restaurant chain decides to randomly sample 35 shipments from the company and finds a mean weight of 24.7 pounds. Test at a 3% level of significance to determine whether or not the food distribution company sends less than 26 pounds of fresh vegetables. a. Check the TWO requirements that are satisfied. The Central Limit Theorem applies. The a distribution is normal since n > 30. The a distribution is normal since the x distribution is normal. The p distribution is normal since np > 5 and nq > 5.A personnel director in a particular state claims that the mean annual income is greater in one of the state's counties (county A) than it is in another county (county B). In County A, a random sample of 18 residents has a mean annual income of $41,100 and a standard deviation of $8200. In County B, a random sample of 8 residents has a mean annual income of $39,100 and a standard deviation of $5900. At a= 0.10, answer parts (a) through (e). Assume the population variances are not equal. If convenient, use technology to solve the problem. The null hypothesis, Ho (b) Find the critical value(s) and identify the rejection region(s). Enter the critical value(s) below. (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) Select the correct rejection region(s) below. O A. - to to O D. t>to (c) Find the standardized test statistic. t= E (Type an integer or decimal rounded to three decimal places as needed.) (d) Decide whether to…Community college instructors' salaries in one state are very low, so low that educators in that state regularly complain about their compensation. The national mean is $57,636$57,636, but instructors from Mississippi claim that the mean in their state is significantly lower. They survey a simple random sample of 3737 colleges in the state and calculate a mean salary of $52,534$52,534 with a standard deviation of $15,791$15,791. Test the instructors' claim at the 0.050.05 level of significance. Step 3 of 3 : Draw a conclusion and interpret the decision.
