Perform the division. 12(r?s?)² -3(rs*)3 4\3

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### Division of Algebraic Expressions

**Problem Statement:**

"Perform the division. See Example 2."

The expression given for division is:

\[ \frac{12(r^2s2)^2}{-3(rs^4)^3} \]

**Steps to Solve:**

1. **Simplify the Numerator:**
   
   - Distribute the exponent 2 across \( r^2 \) and \( s2 \):
     \[ (r^2s2)^2 = (r^2)^2(s2)^2 = r^{4}(2s)^2 = r^4 \cdot 4s^2 = 4r^4s^2 \]
   - Multiply by 12:
     \[ 12 \times 4r^4s^2 = 48r^4s^2 \]

2. **Simplify the Denominator:**
  
   - Distribute the exponent 3 across \( rs^4 \):
     \[ (rs^4)^3 = r^3(s^4)^3 = r^3s^{12} \]
   - Multiply by -3:
     \[ -3 \times r^3s^{12} = -3r^3s^{12} \]

3. **Combine and Simplify the Division:**

   - Write the simplified numerator and denominator:
     \[ \frac{48r^4s^2}{-3r^3s^{12}} \]
   - Factor and reduce the coefficients:
     \[ \frac{48}{-3} = -16 \]
   - Reduce the exponents using \( a^m / a^n = a^{m-n} \):
     \[ \frac{r^4}{r^3} = r^{4-3} = r \]
     \[ \frac{s^2}{s^{12}} = s^{2-12} = s^{-10} = \frac{1}{s^{10}} \]
   - Combine all parts:
     \[ -16 \times r \times \frac{1}{s^{10}} = -\frac{16r}{s^{10}} \]

**Final Answer:**

\[ -\frac{16r}{s^{10}} \]
Transcribed Image Text:### Division of Algebraic Expressions **Problem Statement:** "Perform the division. See Example 2." The expression given for division is: \[ \frac{12(r^2s2)^2}{-3(rs^4)^3} \] **Steps to Solve:** 1. **Simplify the Numerator:** - Distribute the exponent 2 across \( r^2 \) and \( s2 \): \[ (r^2s2)^2 = (r^2)^2(s2)^2 = r^{4}(2s)^2 = r^4 \cdot 4s^2 = 4r^4s^2 \] - Multiply by 12: \[ 12 \times 4r^4s^2 = 48r^4s^2 \] 2. **Simplify the Denominator:** - Distribute the exponent 3 across \( rs^4 \): \[ (rs^4)^3 = r^3(s^4)^3 = r^3s^{12} \] - Multiply by -3: \[ -3 \times r^3s^{12} = -3r^3s^{12} \] 3. **Combine and Simplify the Division:** - Write the simplified numerator and denominator: \[ \frac{48r^4s^2}{-3r^3s^{12}} \] - Factor and reduce the coefficients: \[ \frac{48}{-3} = -16 \] - Reduce the exponents using \( a^m / a^n = a^{m-n} \): \[ \frac{r^4}{r^3} = r^{4-3} = r \] \[ \frac{s^2}{s^{12}} = s^{2-12} = s^{-10} = \frac{1}{s^{10}} \] - Combine all parts: \[ -16 \times r \times \frac{1}{s^{10}} = -\frac{16r}{s^{10}} \] **Final Answer:** \[ -\frac{16r}{s^{10}} \]
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