Perform the balancing Pb(OH)4 +CIO PbO₂ + CI+ OH under basic condition, then match the given items with the choices. Match each item to a choice: ⠀⠀ Choices: no. of moles of water to balance the oxidation half-reaction 2- CIO -> to balance the H₂O in the reduction half-reaction reducing agent oxidation half-reaction #2H₂O no. of moles of OH in the balanced chemical equation oxidizing agent reduction half-reaction #CIO → Cr Pb(OH)42 PbO₂ 1 #20H ⠀ Pb(OH)4²- #30H ⠀ add 2H* in the reactant side add 2H* in the product

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Chapter1: Chemical Foundations
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Perform the balancing Pb(OH)2 + CIO
Match each item to a choice:
Choices:
no. of moles of water to balance the oxidation half-reaction
->
CIO
to balance the H₂O in the reduction half-reaction
PbO₂ + CI+ OH under basic condition, then match the given items with the choices.
reducing agent
oxidation half-reaction
# 2H₂O
oxidizing agent
reduction half-reaction
no. of moles of OH in the balanced chemical equation
#CIO → CI
Pb(OH)4² → PbO2
2 OH
#Pb(OH)4²-
:: 3 ОН
add 2H* in the reactant side
add 2H* in the product
0
Transcribed Image Text:Perform the balancing Pb(OH)2 + CIO Match each item to a choice: Choices: no. of moles of water to balance the oxidation half-reaction -> CIO to balance the H₂O in the reduction half-reaction PbO₂ + CI+ OH under basic condition, then match the given items with the choices. reducing agent oxidation half-reaction # 2H₂O oxidizing agent reduction half-reaction no. of moles of OH in the balanced chemical equation #CIO → CI Pb(OH)4² → PbO2 2 OH #Pb(OH)4²- :: 3 ОН add 2H* in the reactant side add 2H* in the product 0
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