Perform left recursion elimination and remove the common prefixes from the following grammar. Then, find out whether are they LL1 grammar or not. - G1[A]: A aA Bela B-Bbld - G2[A]: A-baBle B-Abbla G3[S]: S-Aalb A-SB B-ab

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Chapter1: Introduction
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1. Perform left recursion elimination and remove the common prefixes from the
following grammar. Then, find out whether are they LL1 grammar or not.
- G1[A]: A aA Bela B→Bbld
G2[A]: A-baBlε
B-Abbla
G3[S]: S-Aalb A SB Bab
-
Hints:
I
- Substitute only the first non-terminal on the right part of each production
• For G2, First you need to substitute A in B Abb with A-baBle, and get B (baBle) bb
then rewrite it to B → babbb | bb
& means nothing, ebb = bb
For G3, you can substitute A in S-Aa with A-SB, or vice versa. They may have different results.
Remember to delete useless productions after the rewrite. But DO NOT change the start symbol
-
-
.
→
Transcribed Image Text:1. Perform left recursion elimination and remove the common prefixes from the following grammar. Then, find out whether are they LL1 grammar or not. - G1[A]: A aA Bela B→Bbld G2[A]: A-baBlε B-Abbla G3[S]: S-Aalb A SB Bab - Hints: I - Substitute only the first non-terminal on the right part of each production • For G2, First you need to substitute A in B Abb with A-baBle, and get B (baBle) bb then rewrite it to B → babbb | bb & means nothing, ebb = bb For G3, you can substitute A in S-Aa with A-SB, or vice versa. They may have different results. Remember to delete useless productions after the rewrite. But DO NOT change the start symbol - - . →
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