%3D Subtract the functions: f(x)- g(x) where f(x) = -3x+2 and g(x) = 4x- 2 h(x) = f(x) – g(x) D - Multiply the functions: f(x) * g(x) where f(x) = -3x +2 and g(x) = 4x- 2 %3D h(x) = f(x) * g(x) = 7. Divide the functions: g(x) f(x) where f(x) = 5x -4 and g(x) = x- 4

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem 5: Subtraction of Functions**

Subtract the functions: \( f(x) - g(x) \) where \( f(x) = -3x + 2 \) and \( g(x) = 4x - 2 \).

\[ h(x) = f(x) - g(x) = \]

---

**Problem 6: Multiplication of Functions**

Multiply the functions: \( f(x) \cdot g(x) \) where \( f(x) = -3x + 2 \) and \( g(x) = 4x - 2 \).

\[ h(x) = f(x) \cdot g(x) = \]

---

**Problem 7: Division of Functions**

Divide the functions: \( \frac{f(x)}{g(x)} \) where \( f(x) = 5x - 4 \) and \( g(x) = x - 4 \).
Transcribed Image Text:**Problem 5: Subtraction of Functions** Subtract the functions: \( f(x) - g(x) \) where \( f(x) = -3x + 2 \) and \( g(x) = 4x - 2 \). \[ h(x) = f(x) - g(x) = \] --- **Problem 6: Multiplication of Functions** Multiply the functions: \( f(x) \cdot g(x) \) where \( f(x) = -3x + 2 \) and \( g(x) = 4x - 2 \). \[ h(x) = f(x) \cdot g(x) = \] --- **Problem 7: Division of Functions** Divide the functions: \( \frac{f(x)}{g(x)} \) where \( f(x) = 5x - 4 \) and \( g(x) = x - 4 \).
**Graphing a Piecewise Function**

1. **Accurately graph the function:**

   \( f(x) = 
   \begin{cases} 
   5, & x \leq -2 \\
   2x - 3, & x > -2 
   \end{cases} \)

   - **Branch 1**: Constant function \( f(x) = 5 \) for \( x \leq -2 \).
   - **Branch 2**: Linear function \( f(x) = 2x - 3 \) for \( x > -2 \).

2. **What is the domain of branch ② in interval notation?**

   - The domain for branch ② \( (2x - 3) \) is \( (-2, \infty) \).

3. **What is the range of branch ② in interval notation?**

   - The range for branch ② \( (2x - 3) \) when \( x > -2 \) is \( (-7, \infty) \).

**Graph Explanation:**

- The grid provided is for plotting the piecewise function. 
- The first branch is a horizontal line at \( y = 5 \) for \( x \leq -2 \). A closed dot at \( (-2, 5) \) indicates the inclusion of the endpoint.
- The second branch is a line starting just after \( x = -2 \). The line begins at an open dot at \( (-2, -7) \) reflecting the point when this branch begins without including \( x = -2 \). The line continues with a slope of 2.
Transcribed Image Text:**Graphing a Piecewise Function** 1. **Accurately graph the function:** \( f(x) = \begin{cases} 5, & x \leq -2 \\ 2x - 3, & x > -2 \end{cases} \) - **Branch 1**: Constant function \( f(x) = 5 \) for \( x \leq -2 \). - **Branch 2**: Linear function \( f(x) = 2x - 3 \) for \( x > -2 \). 2. **What is the domain of branch ② in interval notation?** - The domain for branch ② \( (2x - 3) \) is \( (-2, \infty) \). 3. **What is the range of branch ② in interval notation?** - The range for branch ② \( (2x - 3) \) when \( x > -2 \) is \( (-7, \infty) \). **Graph Explanation:** - The grid provided is for plotting the piecewise function. - The first branch is a horizontal line at \( y = 5 \) for \( x \leq -2 \). A closed dot at \( (-2, 5) \) indicates the inclusion of the endpoint. - The second branch is a line starting just after \( x = -2 \). The line begins at an open dot at \( (-2, -7) \) reflecting the point when this branch begins without including \( x = -2 \). The line continues with a slope of 2.
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