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Percent yield of methyl 3-nitrobenzoate(show working..include compound name or abbreviation)? Working does not need to be shown in conclusion.

Percent yield of methyl 3-nitrobenzoate(show working..include compound name or abbreviation)? Working does not need to be shown in conclusion.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Volume of methyl benzoate used: 6.0 mL
Mass of 1-methyl-3-nitrobenzoate collected: 7.214 grams
Melting Point of 1-methyl-3-nitrobenzoate: 67 C 

please help find %yield given the data

**Percent Yield of Methyl 3-Nitrobenzoate (show working…include compound name or abbreviation)? Working does not need to be shown in conclusion.** **For reaction A —> B** \[ 5.00 \, \text{g A} \times \frac{1 \text{ mol A}}{136 \, \text{g A}} \times \frac{1 \text{ mol B}}{1 \text{ mol A}} \times \frac{181 \, \text{g B}}{1 \text{ mol B}} = 6.65 \, \text{g B} \] \[ 136 \, \text{g A} \quad 1 \text{ mol A} \quad 1 \text{ mol B} \] may be expressed as… \[ 5.00 \, \text{g A} \times (1 \text{ mol A}/136 \, \text{g A}) \times (1 \text{ mol A}/1 \text{ mol B}) \times (181 \, \text{g B}/1 \text{ mol B}) = 6.65 \, \text{g B} \]
Transcribed Image Text:**Percent Yield of Methyl 3-Nitrobenzoate (show working…include compound name or abbreviation)? Working does not need to be shown in conclusion.** **For reaction A —> B** \[ 5.00 \, \text{g A} \times \frac{1 \text{ mol A}}{136 \, \text{g A}} \times \frac{1 \text{ mol B}}{1 \text{ mol A}} \times \frac{181 \, \text{g B}}{1 \text{ mol B}} = 6.65 \, \text{g B} \] \[ 136 \, \text{g A} \quad 1 \text{ mol A} \quad 1 \text{ mol B} \] may be expressed as… \[ 5.00 \, \text{g A} \times (1 \text{ mol A}/136 \, \text{g A}) \times (1 \text{ mol A}/1 \text{ mol B}) \times (181 \, \text{g B}/1 \text{ mol B}) = 6.65 \, \text{g B} \]
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