% Finer• Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle sizedistribution curves are shown in Figure10090807060504030Clay201000.001+Silt0.01Soil ASandSoil B0.11Particle size (mm) - log scaleGravel10SoilALL26 (oven-dried; assume samefor not dried)B Nonplastic1. Which of the two soils, in your opinion, is a better material for the core of a rolled earth dam?PL18

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% Finer • Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure Clay 1- 100 90 80 70 60 50 40 30 20 10 0 0.001 Silt Soil A Sand Soil B 0.01 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A B LL 26 (oven-dried; assume same for not dried) Nonplastic 1. Which of the two soils, in your opinion, is a better material for the core of a rolled earth dam? PL 18

% Finer • Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure Clay 1- 100 90 80 70 60 50 40 30 20 10 0 0.001 Silt Soil A Sand Soil B 0.01 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A B LL 26 (oven-dried; assume same for not dried) Nonplastic 1. Which of the two soils, in your opinion, is a better material for the core of a rolled earth dam? PL 18

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Answer Choices: A) Cl B) ML C) CH D) MH
From a particle size distribution curve of a sandy soil the following were obtain: Size of particle 0.48 mm percentage finer 60;Size of particle 0.33 mm percentage finer 30;Size of particle 0.21 mm percentage finer 10;Size of particle 0.11 mm percentage finer 5;Determine Cc.
The Grain size analyses results are given in Figure 1 for Soils A and B. Answer the following questions: i) The uniformity coefficient, Cu (= D60/D10) for Soil A is ii) Soil B is classified as.. ..... grained soil. iii) If liquid limit (LL) and plastic limit (PL) values of Soil A are given as 65 % and 35%, then the soil is classified as ................. by using plasticity chart provided below. PLASTICITY INDEX (PI) Percentage Smaller 50 40 30 100 90 20 80 70 60 50 40 30 20 10 0 0,001 For clessification of fine-grained soils and fine-grained fraction of course-grained Equation of A-line Horizontal et PI-4 to LL-25.5 Then PI-0.73 (LL-201 Equation of "u-line Vertical et LL-16 to PI-7 then PI-0.9 (LL-8) Z MHO OH ML OL soills 10 Soil A X 20 0,01 0,1 Particle Size (mm) Figure 1.Grain Size Distribution CLOL LOWING 1 CH OH Soil B LIQUID LIMIT (LL) FG4 Plasticity Chart Figure 2. Plasticity Chart 10 Tio
43.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 100 6 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 60 PL 40 ML None of the above. CL CH MH
Question 2 The sieve analysis of soil and the liquid and plastic limits of the fraction passing through the No. 40 sieve are given below. Classify the soils using the AASHTO classification system and give the group indexes. % Passing No. 10: 87 % Passing No. 40: 62 % Passing No. 200: 30 LL = 32 PL = 24 Group classification: Blank 1 Group index: Blank 2
47.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 31 60 0.250 20 100 0.149 18 200 0.074 4 LL 60 PL 40 Determine its classification using USCS. GW SP None of the above SW GP
A sieve analysis of a soil sample of weight (400 g) was performed and the results were as follows. Required 1-Find the% passing and plot the gradient gradient. 2-Find the regularity coefficient and the Cu gradient
Question 3: For an inorganic soil the following grain - size analysis is given. U.S sieve Percent analysis 4 passing 100 10 90 20 64 40 38 80 18 200 13 For this soil, LL=23 and Pl=19, classify the soil by using a. AASHTO b. USCS c. Give group name and group symbols
Q1: Use the USCS to Classify the soil sample with the following data: % passing 4.75 mm Sieve = 64 % passing 75- Sieve =4 Uniformity Coefficient= 7.5 Coefficient of Curvature=2.7 Plasticity index = 2.5 Solution: Q2: Use the USCS to Classify the soil samples with the following data dalla Soil LL PL Group Symbol Soil Name 15 35 25 ABC 8. ८८ 25 45 65 2-Seepage velocity (m/s) = 70 3- Flow rate in (m3/s) = oss and dry ng www Parmbly & volume change decrease Campering wes Toughness and dry strength dease Presby & val change in 10 20 30 40 50- 60 Liepakt. 70 80 Atra -0.73 (W₂-201 90 Q3: For the soil shown below the hydraulic conductivity is (3 m/day). The sample diameter is 1.5 m. The porosity is (30%). Find: 1- Flow velocity (m/s)== 100 110 120 Soil 4 m ITE
P2, 5.4 List the given, required, graph and box the final answer.
Determine: 1. The percent finer in Sieve # 20 2. The percent finer in Sieve # 80 3. D60from the grain-size distribution curve 4. D30from the grain-size distribution curve 5. D10from the grain-size distribution curve 6. The coefficient of gradation 7. The uniformity coefficient Please answer this asap. For upvote. Thank you very much
Q1: A. Answer in True or False 1. A soil has a Cu =1, then it is considered as a poorly graded soll. 2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity car 3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 50% 4. Decreasing water content below shrinkage limit is accompanied with a decreasing in void ra 5. Water molecules are considered polar and known as dipoles. 6. Dry Density is the smallest density. 7. Capillary rise is directly proportional to the pore channel diameter. 8. The unconfined compressive strength is twice the undrained cohesion. 9. Piping or boiling occurs when effective stress equals to zero. 10. It is assumed that the secondary compression begins when the primary conso