Per Capita Income of Delaware Residents In a recent year, Delaware had the highest per capita annual income with $51,803. If o $4850, answer the following questions. Assume that the sample is taken from a large population and the correction factor can be ignored. Use a TI-83 Plus/TI 84 Plus calculator and round the answer to at least four decimal places. Comwond #4 What is the probability in 490) that random queda Marnewin254913 sample of 34 state residents had a mean income less than $49,490.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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6.3. # 4 Please round to 4th decimal place. Please underline awnser.
Per Capita Income of Delaware Residents In a recent year, Delaware had the highest per capita annual income with $51,803.
If o $4850, answer the following questions. Assume that the sample is taken from a large population and the correction factor
can be ignored. Use a TI-83 Plus/TI 84 Plus calculator and round the answer to at least four decimal places.
INITUO
Co
#4
What is
the probability
146.
that
random
Menewa
Bouwe
sample of 34 state residents had a mean income less than $49,490.
Transcribed Image Text:Per Capita Income of Delaware Residents In a recent year, Delaware had the highest per capita annual income with $51,803. If o $4850, answer the following questions. Assume that the sample is taken from a large population and the correction factor can be ignored. Use a TI-83 Plus/TI 84 Plus calculator and round the answer to at least four decimal places. INITUO Co #4 What is the probability 146. that random Menewa Bouwe sample of 34 state residents had a mean income less than $49,490.
Expert Solution
Step 1

according to central limit theorem if sample size is large enough i.e. greater than 30 then sampling distribution of mean is approximately normally distributed with mean equal to population mean μ and standard error  σ /√n.

So first of all we will calculate corresponding z score and then we shall find required probability as follows with the help of normal distribution table.

P(X<x) = p(Z<z)

 

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