Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(). Calculate AHpxnAH(B203(s)]=-1.273.5 kJ/molAH{B5H9(s)] = 73.2 kJ/molAH{H20()) = -285.8 kJ/molfor the combustion of 5.00 mol of BgHg.Multiple Choice9,090 kJ- 22,700 kJ1.45,400 kJ- 8,790 kJ-45,400 kJNext>LEGO

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Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H200). Calculate AHpxn for the combustion of 5.00 mol of BgHg. AH(B203(s)] =-1.273.5 kJ/mol AH{B5H9(s)] = 73.2 kJ/mol AH{(H20()] = -285.8 kJ/mol Multiple Choice -9,090 kJ - 22,700 kJ 1. 45,400 kJ - 8,790 kJ 45,400 kJ Next> LEGO

Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H200). Calculate AHpxn for the combustion of 5.00 mol of BgHg. AH(B203(s)] =-1.273.5 kJ/mol AH{B5H9(s)] = 73.2 kJ/mol AH{(H20()] = -285.8 kJ/mol Multiple Choice -9,090 kJ - 22,700 kJ 1. 45,400 kJ - 8,790 kJ 45,400 kJ Next> LEGO

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(). Calculate AHpxn
AH(B203(s)]=-1.273.5 kJ/mol
AH{B5H9(s)] = 73.2 kJ/mol
AH{H20()) = -285.8 kJ/mol
for the combustion of 5.00 mol of BgHg.
Multiple Choice
9,090 kJ
- 22,700 kJ
1.
45,400 kJ
- 8,790 kJ
-45,400 kJ
Next>
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