PDUPIS aU Du Deviation, S, Of Sample otal number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 9.0.

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Find the standard deviation, s, of sample data summarized in the frequency distribution table given below by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the
total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 9.0.
n(n - 1)
Interval
30-39
40-49
50-59
60-69
70-79
80-89
22
41
15
2
Frequency
1.
Standard deviation = (Round to one decimal place as needed.)
Consider a difference of 20% between two values of a standard deviation to be significant, How does this computed value compare with the given standard deviation, 9.0?
O A. The computed value is significantly greater than the given value.
O B. The computed value is significantly less than the given value.
OC. The computed value is not significantly different from the given value.
Click to select your answer(s).
O vi 8:45
DELL
%23
$
6
7
8.
4.
2
u
r
Transcribed Image Text:Find the standard deviation, s, of sample data summarized in the frequency distribution table given below by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 9.0. n(n - 1) Interval 30-39 40-49 50-59 60-69 70-79 80-89 22 41 15 2 Frequency 1. Standard deviation = (Round to one decimal place as needed.) Consider a difference of 20% between two values of a standard deviation to be significant, How does this computed value compare with the given standard deviation, 9.0? O A. The computed value is significantly greater than the given value. O B. The computed value is significantly less than the given value. OC. The computed value is not significantly different from the given value. Click to select your answer(s). O vi 8:45 DELL %23 $ 6 7 8. 4. 2 u r
Expert Solution
Step 1

Given data is used to fit a standard deviation for the following data. the data is in inclusive so we need to covert into exclusive by adding 0.5 to the upper limit. and subtracting 0.5 to the lower limit. 

Step 2
class interval friquencies(fi) mid values (mi) fi*mi mi-xbar2 fimi-xbar2
29.5-39.5 1 34.5 34.5 463.9716 463.9716

39.5-49.5

22 44.5 979 133.1716 2929.7752
49.5-59.5 41 55.5 2275.5 0.1936 7.9376
59.5-69.5 15 65.5 982.5 89.4916 1342.374
69.5-79.5 5 75.5 377.5 378.6916 1893.458
79.5-89.5 2 85.5 171 867.8916 1735.7832

 Total                         =86                                                            =4820                                                       =8373.2996

Step 3

Mean = fimii=1n÷N =4820/86 = 56.04

Variance =fixi-xbar2÷N =8373.2996/86 = 97.3639 

standard deviation = variance =9.86

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