PDO has imitiated a project to dig new oil well The probabilities of completion of project on time will be significantly affected by rain. The probability that the project will be completed on time with and without rain is 0.42 and 0.88 respectively. If the probabılity that it will rain is 045, then determine the probability that the project will not be completed on time.

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Chapter1: Combinatorial Analysis
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a PDO has mitiated a project to dig new oil well The probabilities of completion of project on
time will be significantly affected by rain. The probability that the project will be completed on
time with and without rain is 0.42 and 0.88 respectively. If the probability that it will rain is
0.45, then determine the probability that the project will not be completed on time.
b. An Oman manufacturing company uses three different analytical plans for the design and
development of a specific product. Basically, they are used three different times due to cost, the
company implements three plans. Plans 1, 2 and 3 are used for 35%, 20% and 45% of products,
respectively. The defect rate (F) is different for the following three plans (D).
PE DI) - 0.03.
P (F D2) = 0.06
PF D3) = 002,
Where, P (F Dj) is the probability of a defective product grven plan Dj
If a random product is observed and found to be defective, what plan was most likely used and
thus responsible?
Transcribed Image Text:a PDO has mitiated a project to dig new oil well The probabilities of completion of project on time will be significantly affected by rain. The probability that the project will be completed on time with and without rain is 0.42 and 0.88 respectively. If the probability that it will rain is 0.45, then determine the probability that the project will not be completed on time. b. An Oman manufacturing company uses three different analytical plans for the design and development of a specific product. Basically, they are used three different times due to cost, the company implements three plans. Plans 1, 2 and 3 are used for 35%, 20% and 45% of products, respectively. The defect rate (F) is different for the following three plans (D). PE DI) - 0.03. P (F D2) = 0.06 PF D3) = 002, Where, P (F Dj) is the probability of a defective product grven plan Dj If a random product is observed and found to be defective, what plan was most likely used and thus responsible?
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