P(C|AUB) P(AUB|C) = P(C|A) + P(C|B), where AnB = 0 = P(A|C') + P(B|C) − P(An B|C) P(Aº|B) = 1 − P(A|B)
P(C|AUB) P(AUB|C) = P(C|A) + P(C|B), where AnB = 0 = P(A|C') + P(B|C) − P(An B|C) P(Aº|B) = 1 − P(A|B)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:P(C|AUB) = P(C|A) + P(C|B), where AnB = 0
P(AUB|C) = P(A|C) + P(B|C) – P(An B|C)
P(A¶|B) = 1 − P(A|B)

Transcribed Image Text:Consider the events A, B and C. Are the following statements always true? Justify your
answer. If true, prove the statement and if not true, give a counter example (Assume that
all conditioning events have positive probability.)
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