PC-PT PC-PT PC4 POPT PE2 PC5 PCPT 2960 24TT Swi 192.168.10.1 192.168.30.1 10.10.10.2 Switth-PT SW3 10.10.20.2 2950T-24 SW2 2811 2811 R3 R2 192.168.20.1 10.10.20.1 10.10.10.1 PC-PT PC-PT PC3 PCO 2811 R1 Q. 2 (a) When dynamic routing would be preferred over static routing? Refer to the above figure, a summarized static route has been configured in Router R1. R1(config)# ip route 192.168.0.0 255.255.0.0 10.10.20.2 Will this command create any problem? Yes or No. Explain.

Q: x5 x6 x6 4(x5)

A:

Q: FIND THE RESULT AX=? computer architecture MOV AX, 4859 MOV CX, 5CDA INC CX XOR AX, CX XCHG AX, CX

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A: Solution:- Each subparts can be calculated as below

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A: Solution)  D) 16 M

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A: Find the required answer given as below:

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A: For the given  address 1752IQ16, address range shall be (b)I:0.0/0-1:0.0/15.

Q: Show your solution. AX = BEDH BX= 4512H| CX= B203H DX=EA35H DS= 2400H SS=5412H ВP-5EF3H SI=DE59H…

A:

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A: Answer to the above question is in step2.

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Q: olve

A: The answer is

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