Pb2+ + 2 e- → Pb (s) ξo = -0.13 V Ag+ + 1 e- → Ag (s) ξo = 0.80 V What is the voltage, at 298 K, of this voltaic cell starting with the following non-standard concentrations: [Pb2+] (aq) = 0.071 M [Ag+] (aq) = 0.81 M Use the Nernst equation: ξ = ξo - (RT/nF) ln Q First calculate the value of Q, and enter it into the first answer box. Q is dimensionless. Then calculate ξ, the non-standard cell potential, and enter its value into the second answer box (remember the unit of ξ is Volts). Q = ξ =
Pb2+ + 2 e- → Pb (s) ξo = -0.13 V Ag+ + 1 e- → Ag (s) ξo = 0.80 V What is the voltage, at 298 K, of this voltaic cell starting with the following non-standard concentrations: [Pb2+] (aq) = 0.071 M [Ag+] (aq) = 0.81 M Use the Nernst equation: ξ = ξo - (RT/nF) ln Q First calculate the value of Q, and enter it into the first answer box. Q is dimensionless. Then calculate ξ, the non-standard cell potential, and enter its value into the second answer box (remember the unit of ξ is Volts). Q = ξ =
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Pb2+ + 2 e- → Pb (s) ξo = -0.13 V
Ag+ + 1 e- → Ag (s) ξo = 0.80 V
What is the voltage, at 298 K, of this voltaic cell starting with the following non-standard concentrations:
[Pb2+] (aq) = 0.071 M
[Ag+] (aq) = 0.81 M
Use the Nernst equation:
ξ = ξo - (RT/nF) ln Q
First calculate the value of Q, and enter it into the first answer box. Q is dimensionless.
Then calculate ξ, the non-standard cell potential, and enter its value into the second answer box (remember the unit of ξ is Volts).
Q =
ξ =
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