P(AUB)=P(A) + P(B) - P(AnB) represents the formula for the...docxMultiple Choiceconditional probabilityaddition ruleaddition rule for two mutually exclusive eventsmultiplication rule5< Prev6 of 18 ⠀⠀♫ e tvNext >ⒸAaWD OShow A

we have to identify term that represent formulaP(A∪B) = P(A)+P(B)-P(A∩B)

Answered: P(AUB)=P(A) + P(B)- P(AnB) represents…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Show that the probability that an event A or an event B or both will occur is given by the formula P(AUB) = P(A)+P(B)– P(AnB), and specialise this formula for the case (a) when A, B are mutually exclusive events and for the case (b) where A, B are statistically independent events. Find the probabilities P(A), P(B) when A, B are statistically independent events such that P(B) = 2P(A) and P(AU B) = 5/8.
Identify why this assignment of probabilities cannot be legitimate: P(A) = 0.4, P(B) = 0.3, and P(A and B)=0.5 (A) A and B are not given as disjoint events (B) A and B are given as independent events (C) P(A and B) cannot be greater than either P(A) or P(B) (D) The assignment is legitimate
Addition of Rule of Probabilities P(A Or B) = P(A) +P(B) – P(A and B) for mutually exclusive events the last part P(A and B) is zero, why?
Timely patching is important for server security. Suppose an organization has 3 servers. Two of them have been patched, while one of them still remains unpatched. The prob- ability an unpatched server gets compromised is, and the probability that a patched server get compromised is p. If an attacker randomly attacks one of the three servers, the probability he compromises the server is (a) What is the value of p? • (b) This time the attacker randomly chose two servers to attack, and observed only one of them got compromised. What is the conditional probability that both attacked servers are patched?
how to identify conditional probability
At the close of the stock markets on a day in 2017, there were 6100 companies listed with certain stock exchanges. On this day, the probabilities of advancing, declining, and unchanged company stocks appears in the table for the two exchanges. Find the probability that a stock was listed on Exchange 2 given that it advanced. Percentage of Probability of Probability of Companies Listed Probability the Stock Stock Stocks Remain Unchanged Exchange Exchange 1 Exchange 2 Advancing Declining 0.5052 0.7237 0.2466 0.0297 0.4948 0.6009 0.3455 0.0536 Let F be Exchange 2 and E be an advance. P(F) = .4948 and P (F') = .5052 The probability that a stock was listed on Exchange 2 given that it advanced is (Do not round until the final answer. Then round to four decimal places as needed.)
In a family of 5 children, find the probability that there are (i) (ii) (ii) (iv) 2 boys At least one boy All are boys No boys
Obstetrics Suppose that infants are classified as low birthweight if they have a birthweight <2,500 g and as normal birthweight if they have a birthweight 22,500 g. Suppose that infants are also classified by length of gestation in the following five categories: <28 weeks, 28-31 weeks, 32-35 weeks, 36 weeks, and 237 weeks. Assume the probabilities of the different periods of gestation are as given in the table below. Length of gestation <28 weeks Probability. 0.006 0.010 28-31 weeks 32-35 weeks 36 weeks 0.035 237 weeks 0.900 The following conditional probabilities are given: assume that the probability of low birthweight is 0.948 given a gestation of <28 weeks, 0.700 given a gestation of 28-31 weeks, 0.432 given a gestation of 32-35 weeks, 0.202 given a gestation of 36 weeks, and 0.028 given a gestation of 237 weeks. (a) What is the probability of having a low birthweight infant? (Round your answer to four decimal places. Hint: Use the Law of Total Probability.) 0.06612 0.049 (b) Show…
An automobile manufacturer produces 49% of its cars at plant A. If 5% of the cars manufactured at plant A have defective emissions control devices, what is the probability that one of this manufacturer's cars was manufactured at plant A and has a defective emissions control device? Probability = (Type an integer or decimal.) C
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P(AUB)=P(A) + P(B)- P(AnB) represents the formula for the. Multiple Choice conditional probability addition rule addition rule for two mutually exclusive events