Patients undergoing an MRI occasionally reportseeing flashes of light. Some practitioners assumethat this results from electric stimulation of the eyeby the emf induced by the rapidly changing fields ofan MRI solenoid. We can do a quick calculation tosee if this is a reasonable assumption. The humaneyeball has a diameter of approximately 25 mm.Rapid changes in current in an MRI solenoid canproduce rapid changes in field, with AB/At aslarge as 52 T/s.For the steps and strategies involved in solving asimilar problem, you may view a Video TutorSolution. Part AWhat emf would this induce in a loop circling the eyeball?Express your answer with the appropriate units.HẢE =ValueUnitsSubmitRequest AnswerPart BHow does this compare to the 15 mV necessary to trigger an action potential?This amount of emf is more than adequate to trigger an action potential.This amount of emf is inadequate to trigger an action potential.This amount of emf is absolutely inadequate to trigger an action potential.This amount of emf is almost adequate to trigger an action potential.

Answer: (A): E = 25.5 mV (B): Option A is correct answer. Detailed solution is given below.…

Answered: Patients undergoing an MRI occasionally…

Similar questions

In situations where a small signal must travel over a distance,a shielded cable is used in which the signal wire is surrounded by an insulator and then enclosed by a cylindricalconductor (shield) carrying the return current. Why is a“shield” necessary?
An MRI technician moves her hand from a region of very low magnetic field strength ( approximately zero) into the MRI scanner's field in a quick motion, taking 3.1 milliseconds. The MRI is essentially a solenoid, with 1500 loops of wire. By doing so, a current of 0.15 milliAmps is induced in her wedding ring. If her wedding ring has a diameter of 1.95 cm and it has measured resistance of 119 Ohms, what is the magnetic field in the MRI.
For a physics lab assignment, a student needs to create a solenoid using copper wire with diameter d = 0.500 mm. The resistance of the solenoid needs to be 3.50 and the magnetic field of the solenoid with a current of 2.90 A should be 5.90 × 10-² T. Assume the resistance does not change significantly with temperature, and the radius of the solenoid is 1.00 cm. (Use p 1.70 x 10-8.m for the resistivity of copper.) (a) How many turns of wire does the student need? turns (b) Determine the required length (in cm) of the solenoid. cm
A capillary tube shaped conductor (silindirik boru) with p resistivity has length d and its dimensions shown in figure. Apply a potential difference Vo is applied between to ends. Show clearly which end positive and negative. a) Show the direction of electric field, current, current density in the conductor. b) Calculate the current density J in the wire c) Calculate the magnetic field everywhere. Show and explain every step by using Ampere's Law. h 1₂
In modern Magnetic Resonance Imaging (MRI), the system is resistance free. The resistance-free Magnetic Resonance Imaging (MRI) is created by submerging the solenoid electromagnet into a cryogenic liquid such as liquid helium (He).eHH The temperature of liquid helium (He) is 4 Kelvin (K), which is -4,520 Fahrenheit (F). What type of magnet creates the resistance-free system?
Ch. 26
Given: B = 5 * 10-5 T ẑ; σ = 4 (Ohm-meters)-1 (conductivity) a) Assume that seawater is moving at a constant velocity v = v0 ŷ and that the Earth’s magnetic field is along the ẑ-direction. Calculate the electric current density J produced by the magnetic force. Hint: first compute the force per unit charge, F/q, and then use the relationship J = σ(F/q). b) Derive the equation of motion of a cylindrical differential volume element of base area δA and height δh parallelto the direction of J. Assume that seawater has a known volumetric mass density ρ. Show that this equation implies that the velocity satisfies the following differential equation:dvy/dt = vy/τwhere τ is a constant that you should write in terms of B, σ, and ρ.
Draw a sketch of the situation in the figure, showing the direction of electrons carrying the current, and use RHR-1 to verify the direction of the force on the wire.
Figure CQ19.7 shows a coaxial cable carrying current I in itsinner conductor and a return current of the same magnitudein the opposite direction in the outer conductor. Themagnetic field strength at r = r0 is B0. Find the ratio B /B0 at(a) r = 2r0 and (b) r = 4r0.