Past experience indicates that the time required for high school seniors to complete a standardized test is a normal random variable with a standard deviation of 4 minutes. Test the hypothesis that a= 4 against the alternative that a<4 if a random sample of the test times of 18 high school seniors has a standard deviation s= 2.01. Use a 0.05 level ofsignificance.Click here to view.cace 1 of the Chi-Square Critical Values Table.Click here to visw paga 2 of tha Chi-Squara Cnitical Valuas Table.Identify the null and altemalive hypolheses. Select the correct chcice below and fill in the answer boxes to complele your choice.(Type integers or decimals. Do not round.)OA H >H, =Critical Valuas af Chi-Squared, Page 1OB. H =HyiOD. HH,i oOC. H =H, aOC.Critinl Vil of the Cl d DistrilatioeIdentify the critical recion. Select the correct choice below and filIl in the answer bosles) to complete vour choice.0.80.95 M TS 70 G0.099 ne 0G A I a D1913 119(Round to two decimal places as needed)01 0.40.713 1302110.0.41219OA r4 0r 297 295 s54 0182 RI L14561.41602196 13573000 4.30.41223OB. or >82 LI34 12370.616I OS9 12 156 10S 134 1647 2002 2.190O LTS 20 28 210 216 2 1cs 124I1 200 10 3ae 1816522430003.41 46T 633%2182242734.5915.527A00 6390 8347 9327.3442.7007S106.TTFind the test statistic.12 2074 1571 41713 3 4.107 4614 4O 4000 a15 401 S10 S12 S8124.14.406.3 7s079.20 9. 123010.16 10s .6.5711.790(Round to two decimal places as needed)I1T 11.7 14.I5.1425812I1912 1244 15.338J0S 12002 12.792 13 53 6331 m HE 17.28ILI2What is the appropriate decision for this test?17 SEST 1.sE6.0819 C54420 74 300 2TTEu MT5.9011.6512443117I6 145 15.152 18.2814678 15.42 162 17OA The test statistic is significant at the 0.05 level. Based on the test statistic, reject H, and conclude that there is sufficient evidence that e< 4.2111.9115.445 1634 17.1 30722 SG 952 100 e 212131140 Ma14 1720 1R 213718.137 19001 21719.T 19 7I89 19 207 21rOB. The test statistic is not signiticant at the 0.05 level. Based on the test statistic, tal to rejact H, and conclude that there is not sufficient evidence that o<4.19611.20148817.18723 3 N T24119012T12.1540OC. The test statistic is not significant at the 0.05 level. Based on the test statistic, reject H, and condude that there is not sufficient evidence that e4.25 10.01411647320 IL13.014.125144T19 13 191 1 15 ET E07 IT12.1915.3717.2902083 21.7 25.3IRI14 20703 211 22719 26.3M21.S8 22 8 2364 27322475 237 24T 323.364 244T 2 29.190OD. The test statistic is significant at the 0.05 level. Based on the test statistic, fail to reject H, and conclude that there is sufficient evidence that e<4.16.11457328 1246113.514414953 16 30197530 137T4.7920.40 20.0726.20.0522.1642.0723.63824.43132.35732.34541.403306SLST2 933517.48540.4246.490.80.000.500.750,70 6.50PrintDoneClick to select your answer(s).

Name: Past experience indicates that the time required for high school seni
Uploaded: 2024-03-20T07:07:00.000Z
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Description: Past experience indicates that the time required for high school seniors to complete a standardized test is a normal random variable with a standard deviation of 4 minutes. Test the hypothesis that a= 4 against the alternative that a<4 if a random s

To test:H0:σ2=16H1:σ2<16because σ=4 So,σ0=4 It is a left tailed test.

Math

Statistics

Past experience indicates that the time required for high school seniors to complete a standardized test is a normal random variable with a standard deviation of 4 minutes. Test the hypothesis that a= 4 against the alternative that a <4 if a random sample of the test times of 18 high school seniors hes a standard deviation s=2.01. Use a 0 significance Click here to view ace 1 of the Chi-Sauare Cilical Values Table. Cick here to view.naca 2 of the Chi Squara Cntical Valuas Table Identily the null and altemalive hypotheses Select the corect cheice below and fil in the answer bexes to complete your choice. (Type integers or decimals. Do not round) A Critical Valuan of Chi-Squared, Page 1 OA H 3. Ha = H, . H, OC. H OD. H Oc. H, H,o Ci Vlf e ChiS Distratin Idenily the critical region. Select the correct choice below and fil in the answer boxes) to complete your choice. (Hound to twe decimal places as neaded) 0.00 0.08 0 M TS 070 0 2 no0 SDOTIT S 4 30 2 5 0412 4 a 0211 .4 0713 139 OA r On for 1213 LI 2.190 1 2 300 4. LIM 1217 2.201 T 12 16I 2 1N2 420 L4TI 6.3 1 4 SOTI A7 7.344 D LT 2 10 216 2 e 1 2. 2 270 24 6.30 4 179 6ar 13N 9342 II 2000 IN EOn I I 41 707 A 9.0 1138 9.0 Find the test statistic. 1a aae 12 2014 A71 41 10 4.0 4000 6.3 141 1.70 9 12.39 14 (Round te twe decimal places as neaded) I1912 12404 15.3 12.192 13 . aes A 173 17 What is the appropriate decision for this test? IN 5 19 es T 6T 11. TIs 1244 14AT AN 16 r 15445 1634 IT 23r 20 144 40 2ST OA The test statistic is significant at the 0.05 level. Based on the test statistic, reject H, and conclude that there is sufficient evidence that e «4. 163 IT 3317 M4 172 1 21.7 I7INT A 13r 190 223T 21 8 A OB. The test statistic is not signiticant at the 0.05 level. Based on the test statistic, tal to rejact H, and conclude that there is not sufticient evidence that o 4 123 18001 14 14 17.187 23 030 I1.200 24 1R 1190e an 1050 U 110 19 2 s 217 21.M 21 2279 M 22 214 e 22 475 23T 24T N 244 2.n 32345 310 SENTI OC. The lest statistic is not significant at the 0.05 level. Based on the test statistic, reject H, and condude that there is not sufficient evidence that e4. 12T 16473 12. 1a 16379 13.00 14126 144 17.29 IR4 2 IR 21 LRA OD. The test statistic is significant at the 0.05 level. Dased on the test statistic, fail to reject H, end conclude that there is sufficient evidence that e<4. 28 124 160 29 13121 30 137T 15 ST4 16 00 20. 23364 40 20 22.104 29.7 en 17.45 24.431 20. 20 1234S 4 37 1.40 man 4292 aam 31.064 46.49 0. Drint Donn