SA0 = 120°SBB Particles A and B are traveling counter-clockwisearound a circular track at a constant speed of 6 m/s. Atthe instant shown the speed of A begins to increase by(ar)A = (0.8sA) m/s² , where sa is in meters.Suppose that r = 6 m . (Figure 1)Determine the distance measured counterclockwise along the track from B to A when t = 1 s.Express your answer to three significant figures and include the appropriate units.

Given data as per the question speed = 6 m/s (αt)A=0.8sA ms2 distance travelled between two…

Answered: Particles A and B are traveling…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

Particles A and B are traveling counter-clockwise
around a circular track at a constant speed of 6 m/s. At
the instant shown the speed of A begins to increase by
(ar)A = (0.8sA) m/s² , where sa is in meters.
Suppose that r = 6 m . (Figure 1)
Determine the distance measured counterclockwise along the track from B to A when t = 1 s.
Express your answer to three significant figures and include the appropriate units.

Expert Solution

Step 1

Given data as per the question

speed = 6 m/s

${(α_{t})}_{A} = 0.8 s_{A} \frac{m}{s^{2}}$

$\begin{array}{l} distance travelled between two particles is d_{o} = 6 \times (\frac{120}{180} π) = 12.566 m \\ w h e n t = 1 s,particle B travels a distance of s_{B} = 6 \times 1 = 6 m \\ the distance travelled by particle A can be obtained as \\ v_{A} d v_{A} = a_{A} d s_{A} \\ \int_{6}^{v_{A}} v_{A} d v_{A} = \int_{0}^{s_{A}} 0.8 s_{A} d s_{A} \\ {[\frac{v_{A}^{2}}{2}]}_{6}^{v_{A}} = {[0.8 \frac{s_{A}^{2}}{2}]}_{0}^{s_{A}} \\ \frac{1}{2} (v_{A}^{2} - 36) = 0.4 s_{A}^{2} \\ v_{A}^{2} = 0.8 s_{A}^{2} + 36 \\ v_{A} = \sqrt{0.8 s_{A}^{2} + 36} \end{array}$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions