Particle A decays with a decay constant 1 to become particle B, which will decay into a C particle with a decay constant of 2, which then decays again into a particle D with a decay constant of 3. Number of particles A as a function time is obtained by solving the differential equation (differential equation in picture number one) The number of particles B as a function of time is expressed by (in picture number 2) Determine the number of particles C as a function of time by solving the differential equation (in picture number 3) if at t = 0, there are only N0 particles A.
Particle A decays with a decay constant 1 to become particle B, which will decay into a C particle with a decay constant of 2, which then decays again into a particle D with a decay constant of 3. Number of particles A as a function time is obtained by solving the differential equation (differential equation in picture number one) The number of particles B as a function of time is expressed by (in picture number 2) Determine the number of particles C as a function of time by solving the differential equation (in picture number 3) if at t = 0, there are only N0 particles A.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Particle A decays with a decay constant 1 to become particle B, which will decay
into a C particle with a decay constant of 2, which then decays again
into a particle D with a decay constant of 3. Number of particles A as a function
time is obtained by solving the differential equation (differential equation in picture number one)
The number of particles B as a function of time is expressed by (in picture number 2)
Determine the number of particles C as a function of time by solving the differential equation (in picture number 3)
if at t = 0, there are only N0 particles A.
Transcribed Image Text:dNa
= -NoA1.
dt
dNº
dNa
- NzA2.
dt
dt
dN.
dNb
NA3,
dt
dt
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