Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Part II. Determination Ka and Molar Mass of Unknown Monoprotic Acio

Part II. Determination Ka and Molar Mass of Unknown Monoprotic Acio

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question

Please check if my second data table is correct. I don't think the molar mass is correct

Part II. Determination Ka and Molar Mass of Unknown Monoprotic Acid Assignment # 2 1 Mass of the acid, in stock solution, g 4.45 2 Volume of the stock solution, ml 250.00 3 Molarity of the standardized NaOH solution, M 0.09 Data Table 1. Titration Data 1 Volume of the Unknown acid used for titration, mL 10.00 Volume of NaOH at equivalence point from first derivative, ml 3 Volume of NaOH at equivalence point from second derivative, mL 2 22.13 22.13 4 Average volume of NaOH for calculations 22.13 Initial pH 3.08 6 pH at equivalence point from Titration Curve Page 8.76 6 pH at half-equivalence point from Titration Curve Page 4.93 7 pH at half-equivalence point from the Graph below 9.15 Data Table 2. Final Results of the Titration of Unknown Acid Moles of NaOH at equivalence point, mol| Moles of Unknown acid at equivalence point, mol Molarity of Unknown acid, M Moles of Unknown acid in the stock solution, mol Molar Mass of Unknown acid, g/mol pH at half-equivalence point 2.02E-03 2.02E-03 8.09E-03 2.02E-03 74.08 3 4 4.93 7 pKa 4.93 8 Ка 1.17E-05 According to Appendix II Unknown acid is identified as Propanoic Acid 2.
Transcribed Image Text:Part II. Determination Ka and Molar Mass of Unknown Monoprotic Acid Assignment # 2 1 Mass of the acid, in stock solution, g 4.45 2 Volume of the stock solution, ml 250.00 3 Molarity of the standardized NaOH solution, M 0.09 Data Table 1. Titration Data 1 Volume of the Unknown acid used for titration, mL 10.00 Volume of NaOH at equivalence point from first derivative, ml 3 Volume of NaOH at equivalence point from second derivative, mL 2 22.13 22.13 4 Average volume of NaOH for calculations 22.13 Initial pH 3.08 6 pH at equivalence point from Titration Curve Page 8.76 6 pH at half-equivalence point from Titration Curve Page 4.93 7 pH at half-equivalence point from the Graph below 9.15 Data Table 2. Final Results of the Titration of Unknown Acid Moles of NaOH at equivalence point, mol| Moles of Unknown acid at equivalence point, mol Molarity of Unknown acid, M Moles of Unknown acid in the stock solution, mol Molar Mass of Unknown acid, g/mol pH at half-equivalence point 2.02E-03 2.02E-03 8.09E-03 2.02E-03 74.08 3 4 4.93 7 pKa 4.93 8 Ка 1.17E-05 According to Appendix II Unknown acid is identified as Propanoic Acid 2.
Titration Curve - pH vs Volume 13.00 12.00 11.00 10.00 9.00 8.00 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 0.00 5.00 10.00 15.00 20.00 25.00 30.00 35.00 Volume of NaOH, ml Equation 1 (Eq 1) y= 0.08x+4.0474 Slope (ml) 0.0800 Intercept (b1) 4.0474 Equation 2 (Eq 2) y= 4.804x-97.314 Slope (m2) 4.804 Intercept (b2) -97.31 Equation 3 (Eq 3) y=0.062x-10.348 Slope (m2) 0.0620 Intercept (b3) 10.348 V1, Volume of NAOH, ml at intercept of Eq 1 and Eq 2 21.46 (b2 - b1) (m1 - m2) v2, Volume of NAOH, ml at intercept of Eq 2 and Eq 3 22.70 (b3 - b1) (m2 - m3) Veg, Volume of NAOH, mL at equivalence point (V2 • V1) /2 22.08 pHeq, pH at equivalence point 8.76 m2 x Veq • b2 Vhalf-eq, Volume of NaOH, ml at half - equivalence point 11.04 Veq 12 pH half-eq, pH at half - equivalence point 4.93 m1x Vhalf-eq • b1 pKa 4.93 Ка 1.17E-05 Hd
Transcribed Image Text:Titration Curve - pH vs Volume 13.00 12.00 11.00 10.00 9.00 8.00 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 0.00 5.00 10.00 15.00 20.00 25.00 30.00 35.00 Volume of NaOH, ml Equation 1 (Eq 1) y= 0.08x+4.0474 Slope (ml) 0.0800 Intercept (b1) 4.0474 Equation 2 (Eq 2) y= 4.804x-97.314 Slope (m2) 4.804 Intercept (b2) -97.31 Equation 3 (Eq 3) y=0.062x-10.348 Slope (m2) 0.0620 Intercept (b3) 10.348 V1, Volume of NAOH, ml at intercept of Eq 1 and Eq 2 21.46 (b2 - b1) (m1 - m2) v2, Volume of NAOH, ml at intercept of Eq 2 and Eq 3 22.70 (b3 - b1) (m2 - m3) Veg, Volume of NAOH, mL at equivalence point (V2 • V1) /2 22.08 pHeq, pH at equivalence point 8.76 m2 x Veq • b2 Vhalf-eq, Volume of NaOH, ml at half - equivalence point 11.04 Veq 12 pH half-eq, pH at half - equivalence point 4.93 m1x Vhalf-eq • b1 pKa 4.93 Ка 1.17E-05 Hd
Expert Solution
steps

Step by step

Solved in 6 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Molecular Interactions in Liquids
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS