Part II: Ksp - Solubility Product PbCl2(s) Pb2+ Volume of 0.30 M Pb(NO3)2 used Moles of Pb(NO3)2 used Volume of 0.30 M HCI used Moles of HCI used 5.0 mL 2.0 5.0 mL 5.0 mL Calculate [Pb²+] and [CI] using moles of each ion in solution and total volume of the final solution. (aq) Volume of H₂O added to dissolve solid Total volume of final solution + 2Cl(aq) Fill in or circle your answer: Reaction 6 shifts Estimate Ksp for PbCl2 using the concentrations above. in hot water and shifts Reaction 6 is exothermic/endothermic. Reaction 6 = moles Pb²+ mL = moles CI™ in cold water. Explain in terms of Le Châtelier's Principle why the PbCl2 dissolved upon addition of water. What did adding water do to the concentrations of ions in solution?

Part II: Ksp - Solubility Product PbCl2(s) Pb2+ Volume of 0.30 M Pb(NO3)2 used Moles of Pb(NO3)2 used Volume of 0.30 M HCI used Moles of HCI used 5.0 mL 2.0 5.0 mL 5.0 mL Calculate [Pb²+] and [CI] using moles of each ion in solution and total volume of the final solution. (aq) Volume of H₂O added to dissolve solid Total volume of final solution + 2Cl(aq) Fill in or circle your answer: Reaction 6 shifts Estimate Ksp for PbCl2 using the concentrations above. in hot water and shifts Reaction 6 is exothermic/endothermic. Reaction 6 = moles Pb²+ mL = moles CI™ in cold water. Explain in terms of Le Châtelier's Principle why the PbCl2 dissolved upon addition of water. What did adding water do to the concentrations of ions in solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Part II: Ksp - Solubility Product
PbCl2(s) = Pb²+ (aq) + 2Cl(aq)
5.0 mL
2,0
5.0
mL
5.0 mL
Calculate [Pb²+] and [Cl] using moles of each ion in solution and total volume of the final solution.
Volume of 0.30 M Pb(NO3)2 used
Moles of Pb(NO3)2 used
Volume of 0.30 M HCI used
Moles of HCI used
Volume of H₂O added to dissolve solid
Total volume of final solution
Estimate Ksp for PbCl2 using the concentrations above.
Fill in or circle your answer:
Reaction 6 shifts
in hot water and shifts
Reaction 6 is exothermic/endothermic.
Reaction 6
= moles Pb²+
mL
= moles Cl
in cold water.
Explain in terms of Le Châtelier's Principle why the PbCl2 dissolved upon addition of water. What
did adding water do to the concentrations of ions in solution?

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