Part II: Ksp - Solubility Product PbCl2(s) Pb2+ Volume of 0.30 M Pb(NO3)2 used Moles of Pb(NO3)2 used Volume of 0.30 M HCI used Moles of HCI used 5.0 mL 2.0 5.0 mL 5.0 mL Calculate [Pb²+] and [CI] using moles of each ion in solution and total volume of the final solution. (aq) Volume of H₂O added to dissolve solid Total volume of final solution + 2Cl(aq) Fill in or circle your answer: Reaction 6 shifts Estimate Ksp for PbCl2 using the concentrations above. in hot water and shifts Reaction 6 is exothermic/endothermic. Reaction 6 = moles Pb²+ mL = moles CI™ in cold water. Explain in terms of Le Châtelier's Principle why the PbCl2 dissolved upon addition of water. What did adding water do to the concentrations of ions in solution?

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Part II: Ksp - Solubility Product
PbCl2(s) = Pb²+ (aq) + 2Cl(aq)
5.0 mL
2,0
5.0
mL
5.0 mL
Calculate [Pb²+] and [Cl] using moles of each ion in solution and total volume of the final solution.
Volume of 0.30 M Pb(NO3)2 used
Moles of Pb(NO3)2 used
Volume of 0.30 M HCI used
Moles of HCI used
Volume of H₂O added to dissolve solid
Total volume of final solution
Estimate Ksp for PbCl2 using the concentrations above.
Fill in or circle your answer:
Reaction 6 shifts
in hot water and shifts
Reaction 6 is exothermic/endothermic.
Reaction 6
= moles Pb²+
mL
= moles Cl
in cold water.
Explain in terms of Le Châtelier's Principle why the PbCl2 dissolved upon addition of water. What
did adding water do to the concentrations of ions in solution?
Transcribed Image Text:Part II: Ksp - Solubility Product PbCl2(s) = Pb²+ (aq) + 2Cl(aq) 5.0 mL 2,0 5.0 mL 5.0 mL Calculate [Pb²+] and [Cl] using moles of each ion in solution and total volume of the final solution. Volume of 0.30 M Pb(NO3)2 used Moles of Pb(NO3)2 used Volume of 0.30 M HCI used Moles of HCI used Volume of H₂O added to dissolve solid Total volume of final solution Estimate Ksp for PbCl2 using the concentrations above. Fill in or circle your answer: Reaction 6 shifts in hot water and shifts Reaction 6 is exothermic/endothermic. Reaction 6 = moles Pb²+ mL = moles Cl in cold water. Explain in terms of Le Châtelier's Principle why the PbCl2 dissolved upon addition of water. What did adding water do to the concentrations of ions in solution?
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