Part II [1 1 0 2 Let B = 2 2 1 1 . Then the dimension of C'(A) is 3 3 1 3 the dimension of C(A") is the dimension of N(A) is and the dimension of N(A') is Following the procedure used in the video to obtain a basis for the column space, our basis will consist of column 1 and column If we used the reduced row echelon form of the matrix to find a basis for the row space (as in the video) then the basis will be 1 1 and 2

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A: Projection matrix onto the column space

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