Part II [1 1 0 2 Let B = 2 2 1 1 . Then the dimension of C'(A) is 3 3 1 3 the dimension of C(A") is the dimension of N(A) is and the dimension of N(A') is Following the procedure used in the video to obtain a basis for the column space, our basis will consist of column 1 and column If we used the reduced row echelon form of the matrix to find a basis for the row space (as in the video) then the basis will be 1 1 and 2
Part II [1 1 0 2 Let B = 2 2 1 1 . Then the dimension of C'(A) is 3 3 1 3 the dimension of C(A") is the dimension of N(A) is and the dimension of N(A') is Following the procedure used in the video to obtain a basis for the column space, our basis will consist of column 1 and column If we used the reduced row echelon form of the matrix to find a basis for the row space (as in the video) then the basis will be 1 1 and 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Part II
1 10 2
Let B =
2 2 1 1. Then the dimension of C(A) is
3 3 1 3
the dimension of C(A") is
the dimension of N(A) is
and the dimension of N(A') is
Following the procedure used in the video to obtain a basis for the
column space, our basis will consist of column 1 and column
If we used the reduced row echelon form of the matrix to
find a basis for the row space (as in the video) then the basis will be
1
1
and
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