PART (I): CONSTANT NET FORCE Data and results Table 1 (mı-m2= 20g) y=(1±0.0005)m Trial | mi(g) m2 (g) 1/(mi+m2) t1(s) t 2(s) t3 (s) E (s) E2(s?) dexp. (g) +0.01s | +0.01s ±0.01s | +0.01s (m/s2) 1 70 50 1.20 0.94 1.07 2 90 70 1.42 1.26 1.25 3 110 90 1.58 1.24 1.41 4 130 110 1.71 1.47 1.44 150 130 1.82 1.34 1.67 Slope = Question (1): From the slope calculate the gravity acceleration g.
PART (I): CONSTANT NET FORCE Data and results Table 1 (mı-m2= 20g) y=(1±0.0005)m Trial | mi(g) m2 (g) 1/(mi+m2) t1(s) t 2(s) t3 (s) E (s) E2(s?) dexp. (g) +0.01s | +0.01s ±0.01s | +0.01s (m/s2) 1 70 50 1.20 0.94 1.07 2 90 70 1.42 1.26 1.25 3 110 90 1.58 1.24 1.41 4 130 110 1.71 1.47 1.44 150 130 1.82 1.34 1.67 Slope = Question (1): From the slope calculate the gravity acceleration g.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
PHYSICS LAB: Newton’s Second Law
Based on the provided formulas on the attached image, Complete the value of the table and answer Question 1.
Transcribed Image Text:Ду
t+a t² → aexp= 2
Ay= Viy
1
а
t2
where Ay : the height of m2 above the
ground when m, on the ground, and t:
the time.
We can see Fnet= (m2-m1)g
(m2-m1
20 g)
Дт
2y
A exp
m, + m2
aexp
slope %3D (mz —т) g
Iexp=??
1
(m1 + m2)
Transcribed Image Text:PART (I): CONSTANT NET FORCE
Data and results
Table 1
(mı-m2 = 20g)
y=(1+0.0005)m
mi(g) m2 (g)
) 1/(m1+m2)
t1(s)
t 2(s)
t3 (s)
t (s)
aexp
(g)
+0.01s | +0.01s +0.01s +0.01s
(m/s2)
1
70
50
1.20
0.94
1.07
2
90
70
1.42
1.26
1.25
3
110
90
1.58
1.24
1.41
4
130
110
1.71
1.47
1.44
5
150
130
1.82
1.34
1.67
Slope =
Question (1): From the slope calculate the gravity acceleration g.
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