Part D Find the equation for the block's position ænew(t) in the new coordinate system. Express your answer in terms of L, xinit » w (Greek letter omega), and t. • View Available Hint(s)

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Chapter1: Units, Trigonometry. And Vectors
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nstants I Perlodic Table
Learning Goal:
x(t) = A cos wt.
To understand the application of the general harmonic
equation to the kinematics of a spring oscillator.
One end of a spring with spring constant k is attached to
Now, imagine that we have exactly the same physical situation but that the x axis is translated, so that the position of
the wall is now defined to be x = 0. (Figure 3)
the wall. The other end is attached to a block of mass m.
The block rests on a frictionless horizontal surface. The
equilibrium position of the left side of the block is defined
to be x =
The initial position of the block is the same as before, but in the new coordinate system, the block's starting position is
0. The length of the relaxed spring is L.
given by xnew (t = 0) = L+xinit -
(Figure 1)
The block is slowly pulled from its equilibrium position to
some position xinit > 0 along the x axis. At time t = 0,
Part D
the block ie releasod with zoro initialvelocitu
Figure
1 of 3
>
Find the equation for the block's position xnew (t) in the new coordinate system.
Express your answer in terms of L, xinit, w (Greek letter omega), and t.
• View Available Hint(s)
L
Xinit
ΑΣφ
?
win
Xnew (t) =
x = 0
Submit
Provide Feedback
Next >
Transcribed Image Text:nstants I Perlodic Table Learning Goal: x(t) = A cos wt. To understand the application of the general harmonic equation to the kinematics of a spring oscillator. One end of a spring with spring constant k is attached to Now, imagine that we have exactly the same physical situation but that the x axis is translated, so that the position of the wall is now defined to be x = 0. (Figure 3) the wall. The other end is attached to a block of mass m. The block rests on a frictionless horizontal surface. The equilibrium position of the left side of the block is defined to be x = The initial position of the block is the same as before, but in the new coordinate system, the block's starting position is 0. The length of the relaxed spring is L. given by xnew (t = 0) = L+xinit - (Figure 1) The block is slowly pulled from its equilibrium position to some position xinit > 0 along the x axis. At time t = 0, Part D the block ie releasod with zoro initialvelocitu Figure 1 of 3 > Find the equation for the block's position xnew (t) in the new coordinate system. Express your answer in terms of L, xinit, w (Greek letter omega), and t. • View Available Hint(s) L Xinit ΑΣφ ? win Xnew (t) = x = 0 Submit Provide Feedback Next >
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