nstants I Perlodic TableLearning Goal:x(t) = A cos wt.To understand the application of the general harmonicequation to the kinematics of a spring oscillator.One end of a spring with spring constant k is attached toNow, imagine that we have exactly the same physical situation but that the x axis is translated, so that the position ofthe wall is now defined to be x = 0. (Figure 3)the wall. The other end is attached to a block of mass m.The block rests on a frictionless horizontal surface. Theequilibrium position of the left side of the block is definedto be x =The initial position of the block is the same as before, but in the new coordinate system, the block's starting position is0. The length of the relaxed spring is L.given by xnew (t = 0) = L+xinit -(Figure 1)The block is slowly pulled from its equilibrium position tosome position xinit > 0 along the x axis. At time t = 0,Part Dthe block ie releasod with zoro initialvelocituFigure1 of 3>Find the equation for the block's position xnew (t) in the new coordinate system.Express your answer in terms of L, xinit, w (Greek letter omega), and t.• View Available Hint(s)LXinitΑΣφ?winXnew (t) =x = 0SubmitProvide FeedbackNext >

Name: nstants I Perlodic TableLearning Goal:x(t) = A cos wt.To understand t
Uploaded: 2024-03-20T06:57:47.000Z
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Description: nstants I Perlodic TableLearning Goal:x(t) = A cos wt.To understand the application of the general harmonicequation to the kinematics of a spring oscillator.One end of a spring with spring constant k is attached toNow, imagine that we have exactly t